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dropping infinite values from dataframes in pandas?
...nf, -np.inf])
In [12]: df.replace([np.inf, -np.inf], np.nan)
Out[12]:
0
0 1
1 2
2 NaN
3 NaN
The same method would work for a Series.
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How does Java handle integer underflows and overflows and how would you check for it?
...tic boolean willAdditionOverflow(int left, int right) {
if (right < 0 && right != Integer.MIN_VALUE) {
return willSubtractionOverflow(left, -right);
} else {
return (~(left ^ right) & (left ^ (left + right))) < 0;
}
}
public static boolean willSubtracti...
How to write asynchronous functions for Node.js
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edited Aug 1 '11 at 14:30
answered Aug 1 '11 at 13:20
Ray...
Ternary operator is twice as slow as an if-else block?
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10 Answers
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Android OpenGL ES and 2D
...ave your canvas set up, you start by calling something like:
gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
After that you're ready to render a sprite.
First, you'll need to load the sprite into a texture: http://qdevarena.blogspot.com/2009/02/how-to-load-texture-in-android-opengl.html
However, this is the...
Accessing nested JavaScript objects and arays by string path
... // strip a leading dot
var a = s.split('.');
for (var i = 0, n = a.length; i < n; ++i) {
var k = a[i];
if (k in o) {
o = o[k];
} else {
return;
}
}
return o;
}
Usage::
Object.byString(someObj, 'part3[0].name');
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Drawing an image from a data URL to a canvas
...t('2d');
var img = new Image;
img.onload = function(){
ctx.drawImage(img,0,0); // Or at whatever offset you like
};
img.src = strDataURI;
Edit: I previously suggested in this space that it might not be necessary to use the onload handler when a data URI is involved. Based on experimental tests f...
Fastest way to check if string contains only digits
...tsOnly(string str)
{
foreach (char c in str)
{
if (c < '0' || c > '9')
return false;
}
return true;
}
Will probably be the fastest way to do it.
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Write bytes to file
I have a hexadecimal string (e.g 0CFE9E69271557822FE715A8B3E564BE ) and I want to write it to a file as bytes. For example,
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Java: random long number in 0
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Starting from Java 7 (or Android API Level 21 = 5.0+) you could directly use ThreadLocalRandom.current().nextLong(n) (for 0 ≤ x < n) and ThreadLocalRandom.current().nextLong(m, n) (for m ≤ x < n). See @Alex's answer for detail.
If you are stuck with Java 6 (or A...