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What is the difference between the mouseover and mouseenter events?
I have always used the mouseover event, but while reading the jQuery documentation I found mouseenter . They seem to function exactly the same.
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How do I find if a string starts with another string in Ruby?
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How to get the currently logged in user's user id in Django?
How to get the currently logged-in user's id?
4 Answers
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Object.getOwnPropertyNames vs Object.keys
What's the difference between Object.getOwnPropertyNames and Object.keys in javascript? Also some examples would be appreciated.
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How do I run a single test with Nose in Pylons
I have a Pylons 1.0 app with a bunch of tests in the test/functional directory.
I'm getting weird test results and I want to just run a single test.
The nose documentation says I should be able to pass in a test name at the command line but I get ImportErrors no matter what I do
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How to apply a style to an embedded SVG?
When an SVG is directly included in a document using the <svg> tag, you can apply CSS styles to the SVG via the document's stylesheet. However, I am trying to apply a style to an SVG which is embedded (using the <object> tag).
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Convert UTC to local time in Rails 3
I'm having trouble converting a UTC Time or TimeWithZone to local time in Rails 3.
6 Answers
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Eclipse: How do you change the highlight color of the currently selected method/expression?
In eclipse, when your cursor is placed on a method (or other things), other places the method exists are highlighted. I'd like to change the color of this highlight, but after scouring the eclipse preferences many times in all 3 places, I have yet to find it.
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Does BroadcastReceiver.onReceive always run in the UI thread?
In my App, I create a custom BroadcastReceiver and register it to my Context manually via Context.registerReceiver . I also have an AsyncTask that dispatches notifier-Intents via Context.sendBroadcast . The intents are sent from a non-UI worker thread, but it seems that BroadcastReceiver.onRe...
Resolving ambiguous overload on function pointer and std::function for a lambda using +
In the following code, the first call to foo is ambiguous, and therefore fails to compile.
1 Answer
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