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PHP “pretty print” json_encode [duplicate]
I'm working on a script that creates a JSON file. Right now I'm just using json_encode (PHP 5.2.x) to encode an array into JSON output. Then I print the returned value to a file and save it. Problem is that the client wants to be able to open these JSON files for readability, so I'd like to add li...
Find and replace Android studio
...) and also maintain case, either in android studio or using a command line script?
10 Answers
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php发送get、post请求的几种方法 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...$URL);
// Building referrer
if($referrer=="") // if not given use this script as referrer
$referrer="111";
// making string from $data
foreach($data as $key=>$value)
$values[]="$key=".urlencode($value);
$data_string=implode("&",$values);
// Find out which port is needed - if not give...
Disable password authentication for SSH [closed]
...
Here's a script to do this automatically
# Only allow key based logins
sed -n 'H;${x;s/\#PasswordAuthentication yes/PasswordAuthentication no/;p;}' /etc/ssh/sshd_config > tmp_sshd_config
cat tmp_sshd_config > /etc/ssh/sshd_conf...
Undo scaffolding in Rails
...db: rake db:rollback
For Scaffold:
rails destroy scaffold Name_of_script
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Separate REST JSON API server and client? [closed]
... who are ready to cope w/ the reality of a site experience that is 70% javascript and what that means.
I do think this is the future of all web-apps.
Some thoughts for the web front end folks (which is where all the new-ness/challenge is given this architecture):
CoffeeScript. Much easier to pr...
How to change a table name using an SQL query?
...ill give you:
Caution: Changing any part of an object name could break scripts and
stored procedures.
but your table name will be changed.
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var.replace is not a function
I'm using the below code to try to trim the string in Javascript but am getting the error mentioned in the title:
10 Answer...
How to get the python.exe location programmatically? [duplicate]
Basically I want to get a handle of the python interpreter so I can pass a script file to execute (from an external application).
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Whether a variable is undefined [duplicate]
...ease use typeof(var) === 'undefined' as undefined is not a constant in JavaScript.
– JonnyReeves
Feb 12 '12 at 10:21
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