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Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array
I need to check a JavaScript array to see if there are any duplicate values. What's the easiest way to do this? I just need to find what the duplicated values are - I don't actually need their indexes or how many times they are duplicated.
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How to close current tab in a browser window?
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You will need Javascript to do this. Use window.close():
close();
Note: the current tab is implied. This is equivalent:
window.close();
or you can specify a different window.
So:
function close_window() {
if (confirm("Close Window?")...
Appending to an object
I have an object that holds alerts and some information about them:
13 Answers
13
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how to implement a pop up dialog box in iOS
After a calculation, I want to display a pop up or alert box conveying a message to the user. Does anyone know where I can find more information about this?
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How to get the browser language using JavaScript [duplicate]
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Try this script to get your browser language
<script type="text/javascript">
var userLang = navigator.language || navigator.userLanguage;
alert ("The language is: " + userLang);
</script>
Cheers
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What's “this” in JavaScript onclick?
What does this mean in the script?
8 Answers
8
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How to detect online/offline event cross-browser?
...r agent will
not contact the network when the user
follows links or when a script
requests a remote page (or knows that
such an attempt would fail), and must
return true otherwise.
Finally, the spec notes:
This attribute is inherently
unreliable. A computer can be
connected to a network without ha...
Best way to store JSON in an HTML attribute?
...to attribute sizes.
If you do run into them, then store the data in a <script>. Define an object and map element ids to property names in that object.
What if the JSON contains special characters? (e.g. {test: '<"myString/>'})
Just follow the normal rules for including untrusted d...
click or change event on radio using jquery
...input type="radio" name="radioName" value="2" />two
</form>
<script>
$('#myForm input[type=radio]').change(function() {
alert(this.value);
});
</script>
You must make sure that you initialized jquery above all other imports and javascript functions. Because $ is a ...
Check if element is visible in DOM
...e display style property. Just make sure that the element isn't fixed. A script to check this, if you have no position: fixed; elements on your page, might look like:
// Where el is the DOM element you'd like to test for visibility
function isHidden(el) {
return (el.offsetParent === null)
}
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