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Parse RSS with jQuery
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WARNING
The Google Feed API is officially deprecated and doesn't work anymore!
No need for a whole plugin. This will return your RSS as a JSON object to a callback function:
function parseRSS(url, callback) {
$.ajax({
url: doc...
Using psql how do I list extensions installed in a database?
... = 'pg_catalog.pg_extension'::pg_catalog.regclass
ORDER BY 1;
Thanks to https://blog.dbi-services.com/listing-the-extensions-available-in-postgresql/
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Naming convention for utility classes in Java
...eUploader: {
brandingHtml: "Powered by \u003ca href=\"https://imgur.com/\"\u003e\u003csvg class=\"svg-icon\" width=\"50\" height=\"18\" viewBox=\"0 0 50 18\" fill=\"none\" xmlns=\"http://www.w3.org/2000/svg\"\u003e\u003cpath d=\"M46.1709 9.17788C46.1709 8.26454 46.2665 7.94324 4...
Is it possible to hide extension resources in the Chrome web inspector network tab?
...was first answered, it was not possible, The OP then requested for it here https://code.google.com/p/chromium/issues/detail?id=239401 and now it is possible.
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Node.js: How to send headers with form data using request module?
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How to master AngularJS? [closed]
...on the mailing list for problems/solutions discussed by community members. https://groups.google.com/forum/?fromgroups#!forum/angular . It's been really useful to me.
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How do I browse an old revision of a Subversion repository through the web view?
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From the web, you can go to the repository SVN page and add / after it:
https://<host>/subversion/source/<revision>
for example:
https://app.assembla.com/spaces/myproject/subversion/source/1200
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How to get JSON from URL in JavaScript?
...'t want to use jQuery you should look at this answer for pure JS solution: https://stackoverflow.com/a/2499647/1361042
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Intellij IDEA generate for-each/for keyboard shortcut
...st
Cmd+Alt+J or Ctrl+Alt+J
Choose Iterate Iterable from the dropdown (i)
https://www.jetbrains.com/phpstorm/help/creating-code-constructs-using-surround-templates.html
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Using Regex to generate Strings rather than match them
...the comments, there is a library available at Google Code to achieve this:
https://code.google.com/archive/p/xeger/
See also https://github.com/mifmif/Generex as suggested by Mifmif
Original message:
Firstly, with a complex enough regexp, I believe this can be impossible. But you should be able to p...