大约有 33,000 项符合查询结果(耗时:0.0411秒) [XML]
Tell Ruby Program to Wait some amount of time
...e can be an integer or float.
Also, if you're writing this within a Rails app, or have included the ActiveSupport library in your project, you can construct longer intervals using the following convenience syntax:
sleep(4.minutes)
# or, even longer...
sleep(2.hours); sleep(3.days) # etc., etc.
# o...
Set margins in a LinearLayout programmatically
...lity function that converts dips to px. This is what I have done in all my apps. Android API sucks.
– mxcl
Jan 26 '12 at 12:00
...
get the latest fragment in backstack
...
RTFM: developer.android.com/reference/android/app/…
– artkoenig
Apr 5 '15 at 10:04
1
...
How do I create a class instance from a string name in ruby?
...ecord model this won't work for me but it will be useful in my "pure" ruby apps :)
– mhenrixon
May 7 '11 at 23:12
1
...
What is the right way to check for a null string in Objective-C?
I was using this in my iPhone app
20 Answers
20
...
How can I catch a ctrl-c event?
...
For a Windows console app, you want to use SetConsoleCtrlHandler to handle CTRL+C and CTRL+BREAK.
See here for an example.
share
|
improve this ...
Prevent text selection after double click
I'm handling the dblclick event on a span in my web app. A side-effect is that the double click selects text on the page. How can I prevent this selection from happening?
...
Fully custom validation error message with Rails
... Lovely. I was looking for getting a one-liner message for my API app and you have shown me how to manipulate the errors class. TY
– ARK
Aug 7 at 15:02
add a comment
...
How to set a timer in android
...u want to user the Alarm Manager ( developer.android.com/reference/android/app/AlarmManager.html ) for running tasks far in the future.
– Kurtis Nusbaum
Oct 15 '11 at 4:16
9
...
How to get Resource Name from Resource id
...esources().getResourceEntryName(int resid);
to get string like com.sample.app:id/radio1:
getResources().getResourceName(int resid);
In Kotlin Now :
val name = v.context.resources.getResourceEntryName(v.id)
share
...
