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How to get a list of MySQL views?
I'm looking for a way to list all views in a database.
9 Answers
9
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How to get the value from the GET parameters?
...aracter on to the end of the URL or the start of the fragment identifier (#foo), whichever comes first.
Then you can parse it with this:
function parse_query_string(query) {
var vars = query.split("&");
var query_string = {};
for (var i = 0; i < vars.length; i++) {
var pai...
Is a LINQ statement faster than a 'foreach' loop?
...t foreach, but most likely you wouldn't have done a blanket "select * from foo" anyway, so that isn't necessarily a fair comparison.
Re PLINQ; parallelism may reduce the elapsed time, but the total CPU time will usually increase a little due to the overheads of thread management etc.
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AngularJS. How to call controller function from outside of controller component
... storing the scope in a global variable:
var scopeHolder;
angular.module('fooApp').controller('appCtrl', function ($scope) {
$scope = function bar(){
console.log("foo");
};
scopeHolder = $scope;
})
call from custom code:
scopeHolder.bar()
if you wants to restrict th...
How to dynamically load a Python class
...dule you're importing. Thus, something like this won't work:
__import__('foo.bar.baz.qux')
You'd have to call the above function like so:
my_import('foo.bar.baz.qux')
Or in the case of your example:
klass = my_import('my_package.my_module.my_class')
some_object = klass()
EDIT: I was a bit...
Using CSS to affect div style inside iframe
Is it possible to change styles of a div that resides inside an iframe on the page using CSS only?
13 Answers
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Get list of data-* attributes using javascript / jQuery
...n - For getting a single value, don't overthink it: el.getAttribute("data-foo"). I've updated my answer to show how you could set data attributes based on an object.
– gilly3
Feb 20 '15 at 22:28
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How to check for changes on remote (origin) Git repository?
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Get last result in interactive Python shell
...t is possible to edit ranges of lines with the %ed macro too:
In [1]: def foo():
...: print "bar"
...:
...:
In [2]: foo()
bar
In [3]: %ed 1-2
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Can we have functions inside functions in C++?
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No.
What are you trying to do?
workaround:
int main(void)
{
struct foo
{
void operator()() { int a = 1; }
};
foo b;
b(); // call the operator()
}
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