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How can I show dots (“…”) in a span with hidden overflow?
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answered Jul 11 '12 at 5:51
sandeepsandeep
83.4k2323 gold badges127127 silver badges149149 bronze badges
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Add a property to a JavaScript object using a variable as the name?
... This question is about modifying existing object, not creating a new one.
– Michał Perłakowski
Dec 26 '15 at 10:16
31
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How to update a record using sequelize for node?
...after reading its documentation, it's obvious that you are instantiating a new object, that's why Sequelize inserts a new record into the db.
First you need to search for that record, fetch it and only after that change its properties and update it, for example:
Project.find({ where: { title: 'aPr...
Get data from file input in JQuery
... }
else {
var file = input.files[0];
var fr = new FileReader();
fr.onload = receivedText;
//fr.readAsText(file);
//fr.readAsBinaryString(file); //as bit work with base64 for example upload to server
fr.readAsDataURL(file);
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Is Ruby pass by reference or by value?
...d probably some oversimplification):
Q1: What happens when you assign a new variable str to a value of 'foo'?
str = 'foo'
str.object_id # => 2000
A: A label called str is created that points at the object 'foo', which for the state of this Ruby interpreter happens to be at memory location...
Android-java- How to sort a list of objects by a certain value within the object
...t {
public static void main(String args[]){
ToSort toSort1 = new ToSort(new Float(3), "3");
ToSort toSort2 = new ToSort(new Float(6), "6");
ToSort toSort3 = new ToSort(new Float(9), "9");
ToSort toSort4 = new ToSort(new Float(1), "1");
ToSort toSort5 = n...
How to update the value stored in Dictionary in C#?
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Just point to the dictionary at given key and assign a new value:
myDictionary[myKey] = myNewValue;
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How to get duplicate items from a list using LINQ? [duplicate]
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Here's another option:
var list = new List<string> { "6", "1", "2", "4", "6", "5", "1" };
var set = new HashSet<string>();
var duplicates = list.Where(x => !set.Add(x));
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How to ignore a property in class if null, using json.net
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As per James Newton King: If you create the serializer yourself rather than using JavaScriptConvert there is a NullValueHandling property which you can set to ignore.
Here's a sample:
JsonSerializer _jsonWriter = new JsonSerializer {
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Remove all elements contained in another array
...d for computing the different elements of two arrays:
const myArray = new Set(['a', 'b', 'c', 'd', 'e', 'f', 'g']);
const toRemove = new Set(['b', 'c', 'g']);
const difference = new Set([...myArray].filter((x) => !toRemove.has(x)));
console.log(Array.from(difference)); // ["a", "d", "...