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Create an Android Jar library for distribution
...e, will you be able to use your jar library still in projects for a higher API level?
– Fran Marzoa
Oct 31 '12 at 18:20
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FileNotFoundException while getting the InputStream object from HttpURLConnection
...I've only hands on experience with JAX-WS/RS from the standard Java EE 5/6 API. I'd suggest to put a breakpoint on the method responsible for processing the XML file and then step further from there.
– BalusC
Mar 21 '11 at 15:31
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Purpose of Activator.CreateInstance with example?
...p()' method above to use (as above). Has something changed in the new .NET APIs?
– Sam
May 6 '15 at 14:36
It's still t...
How to send a JSON object over Request with Android?
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HttpPost is deprecated by Android Api Level 22. So, Use HttpUrlConnection for further.
public static String makeRequest(String uri, String json) {
HttpURLConnection urlConnection;
String url;
String data = json;
String result = null;
try ...
Can I click a button programmatically for a predefined intent?
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API level 15 or higher required
– alexrnov
Aug 30 at 0:28
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Path.Combine absolute with relative path strings
...ually exists, the executing process needs FileIOPermission - true for both APIs. (see MSDN)
– Paul Williams
Jan 30 '15 at 19:06
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Using 'starts with' selector on individual class names
... find a bunch of other cool variations of the jQuery selector here
https://api.jquery.com/category/selectors/
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Import package.* vs import package.SpecificType [duplicate]
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Take a look at the java API, and you'll see many classes and interfaces with the same name in different packages.
For example:
java.lang.reflect.Array
java.sql.Array
So, if you import java.lang.reflect.* and java.sql.* you'll have a collision on...
How to implement an abstract class in ruby?
...ement #{name}.")
end
END
# important that this END is capitalized, since it marks the end of <<-END
end
end
end
require 'rubygems'
require 'rspec'
describe "abstract methods" do
before(:each) do
@klass = Class.new do
extend Abstract
abstract_metho...
Check if object is a jQuery object
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You may also use the .jquery property as described here: http://api.jquery.com/jquery-2/
var a = { what: "A regular JS object" },
b = $('body');
if ( a.jquery ) { // falsy, since it's undefined
alert(' a is a jQuery object! ');
}
if ( b.jquery ) { // truthy, since it's a string...