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Android: How can I get the current foreground activity (from a service)?
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I have a service running on the background, and I would like to update my current Activity when an event occurs (in the service). Is there a easy way to do that (like the one I suggested above)?
Send a broadcast Intent to the activity -- here is a sample project demonstrating this pattern
Hav...
Linux c++ error: undefined reference to 'dlopen'
...he compiler flag under Project>Properties>C/C++Build>Settings>(My Linker)>Miscellaneous in the Linker flags text field. It did nothing.
– MirroredFate
Feb 2 '13 at 7:09
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libxml install error using pip
This is my error:
28 Answers
28
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Android file chooser [closed]
...oader. And I hence I need a file chooser but I don't want to write this by myself. I find OI file manager and I think it suits me.
But how can I force user to install OI file manager?
If I cannot , is there a better way to include a file manager in my app?
Thx
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How do I format a Microsoft JSON date?
I'm taking my first crack at Ajax with jQuery. I'm getting my data onto my page, but I'm having some trouble with the JSON data that is returned for Date data types. Basically, I'm getting a string back that looks like this:
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AES Encryption for an NSString on the iPhone
...easePool * pool = [[NSAutoreleasePool alloc] init];
NSString *key = @"my password";
NSString *secret = @"text to encrypt";
NSData *plain = [secret dataUsingEncoding:NSUTF8StringEncoding];
NSData *cipher = [plain AES256EncryptWithKey:key];
printf("%s\n", [[cipher description] UT...
NoClassDefFoundError: android.support.v7.internal.view.menu.MenuBuilder
...ning Android 4.2. I keep getting crashes with the following stack trace in my Developer Console:
10 Answers
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Java - get the current class name?
...urrent class name, and java appends a useless non-sense $1 to the end of my class name. How can I get rid of it and only return the actual class name?
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Rails 4 Authenticity Token
...s 4.1.6, I had to specify skip_before_action :verify_authenticity_token on my API's application controller as well to make this work.
– Waseem
Oct 1 '14 at 2:48
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TypeError: $.ajax(…) is not a function?
I'm trying to create a simple AJAX request which returns some data from a MySQL database. Here's my function below:
13 Answ...