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C# - Keyword usage virtual+override vs. new
...a Bar, but we are storing it in a variable of type Foo (this is similar to casting it)
Then the result will be as follows, depending on whether you used virtual/override or new when declaring your classes.
share
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PostgreSQL return result set as JSON array?
...t them:
SELECT to_jsonb(array_agg(t)) FROM t
or combine json_agg with a cast:
SELECT json_agg(t)::jsonb FROM t
My testing suggests that aggregating them into an array first is a little faster. I suspect that this is because the cast has to parse the entire JSON result.
9.2
9.2 does not have ...
How to throw std::exceptions with variable messages?
...lt;< foo << 13 << ", bar" << myData); // implicitly cast to std::string
throw std::runtime_error(Formatter() << foo << 13 << ", bar" << myData >> Formatter::to_str); // explicitly cast to std::string
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C++ templates Turing-complete?
...= config::position };
typedef typename Conditional<
static_cast<int>(GetSize<typename config::input>::value)
<= static_cast<int>(position),
AppendItem<InputBlank, typename config::input>,
Identity<typename config::input>&g...
Creating Unicode character from its number
...
Just cast your int to a char. You can convert that to a String using Character.toString():
String s = Character.toString((char)c);
EDIT:
Just remember that the escape sequences in Java source code (the \u bits) are in HEX, so ...
Sql Server string to date conversion
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Try this
Cast('7/7/2011' as datetime)
and
Convert(varchar(30),'7/7/2011',102)
See CAST and CONVERT (Transact-SQL) for more details.
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How to get rid of `deprecated conversion from string constant to ‘char*’` warnings in GCC?
...alise strings that will be modified, because they are of type const char*. Casting away the constness to later modify them is undefined behaviour, so you have to copy your const char* strings char by char into dynamically allocated char* strings in order to modify them.
Example:
#include <iostr...
How to determine if a string is a number with C++?
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You can do it the C++ way with boost::lexical_cast. If you really insist on not using boost you can just examine what it does and do that. It's pretty simple.
try
{
double x = boost::lexical_cast<double>(str); // double could be anything with >> operato...
Java: Date from unix timestamp
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The cast to (long) is very important: without it the integer overflows.
– mneri
Jun 11 '14 at 17:18
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Test if a property is available on a dynamic variable
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@ministrymason If you mean casting to IDictionary and work with that, that works only on ExpandoObject, it won't work on any other dynamic object.
– svick
Jul 12 '12 at 16:58
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