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Round to at most 2 decimal places (only if necessary)
I'd like to round at most 2 decimal places, but only if necessary .
79 Answers
79
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How to check if all elements of a list matches a condition?
I have a list consisting of like 20000 lists. I use each list's 3rd element as a flag. I want to do some operations on this list as long as at least one element's flag is 0, it's like:
...
Rspec: “array.should == another_array” but without concern for order
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265
Try array.should =~ another_array
The best documentation on this I can find is the code itsel...
What's the best practice to round a float to 2 decimals? [duplicate]
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I was working with statistics in Java 2 years ago and I still got the codes of a function that allows you to round a number to the number of decimals that you want. Now you need two, but maybe you would like to try with 3 to compare results, and this function giv...
counting number of directories in a specific directory
...* -maxdepth 0 -type d | wc -l
11
$ find .vim/ -maxdepth 1 -type d | wc -l
12
You can also use ls:
$ ls -l .vim | grep -c ^d
11
$ ls -l .vim
total 52
drwxrwxr-x 3 anossovp anossovp 4096 Aug 29 2012 after
drwxrwxr-x 2 anossovp anossovp 4096 Aug 29 2012 autoload
drwxrwxr-x 13 anossovp anossovp...
How to filter object array based on attributes?
...p;&
el.sqft >= 500 &&
el.num_of_beds >=2 &&
el.num_of_baths >= 2.5;
});
Live Example:
var obj = {
'homes': [{
"home_id": "1",
"price": "925",
"sqft": "1100",
"num_of_beds": "2",
...
How do I obtain the frequencies of each value in an FFT?
... where Fs is the sample rate and N is the size of the FFT. The next bin is 2 * Fs / N. To express this in general terms, the nth bin is n * Fs / N.
So if your sample rate, Fs is say 44.1 kHz and your FFT size, N is 1024, then the FFT output bins are at:
0: 0 * 44100 / 1024 = 0.0 Hz
1: ...
Replace values in list using Python [duplicate]
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207
Build a new list with a list comprehension:
new_items = [x if x % 2 else None for x in items]...
Boolean operators && and ||
...rter ones are vectorized, meaning they can return a vector, like this:
((-2:2) >= 0) & ((-2:2) <= 0)
# [1] FALSE FALSE TRUE FALSE FALSE
The longer form evaluates left to right examining only the first element of each vector, so the above gives
((-2:2) >= 0) && ((-2:2) <...