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Python 3 turn range to a list

I'm trying to make a list with numbers 1-1000 in it. Obviously this would be annoying to write/read, so I'm attempting to make a list with a range in it. In Python 2 it seems that: ...
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How can I add items to an empty set in python

... | edited Jul 7 '13 at 10:28 answered Jul 7 '13 at 10:23 ...
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How can you sort an array without mutating the original array?

... Putzi SanPutzi San 2,38011 gold badge1414 silver badges2626 bronze badges ...
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Counting inversions in an array

...on in java. long merge(int[] arr, int[] left, int[] right) { int i = 0, j = 0, count = 0; while (i < left.length || j < right.length) { if (i == left.length) { arr[i+j] = right[j]; j++; } else if (j == right.length) { arr[i+j] = lef...
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mongodb group values by multiple fields

... 207 TLDR Summary In modern MongoDB releases you can brute force this with $slice just off the basi...
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How does one make random number between range for arc4random_uniform()?

...m(UInt32). I attempted using the range of (1..7) to avoid randomly getting 0 however that returned an error which I didn't enjoy too much. I tried to do this: ...
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How to programmatically set the layout_align_parent_right attribute of a Button in Relative Layout?

... 640 You can access any LayoutParams from code using View.getLayoutParams. You just have to be very a...
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How to pass an ArrayList to a varargs method parameter?

...toArray(new WorldLocation[locations.size()])) (toArray(new WorldLocation[0]) also works, but you would allocate a zero length array for no reason.) Here's a complete example: public static void method(String... strs) { for (String s : strs) System.out.println(s); } ... List&lt...
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convert streamed buffers to utf8-string

... edited Jul 19 '16 at 19:20 Sharikov Vladislav 5,88144 gold badges3636 silver badges7171 bronze badges a...
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How to calculate the number of days between two dates? [duplicate]

... const oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds const firstDate = new Date(2008, 1, 12); const secondDate = new Date(2008, 1, 22); const diffDays = Math.round(Math.abs((firstDate - secondDate) / oneDay)); ...