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Editing legend (tem>x m>t) labels in ggplot
...ion seems to solve my problem. When using ggplot I can't get the right tem>x m>t in the legend, even though it's in my dataframe. I have tried scale_colour_manual , scale_fill_manual with different values for labels= such as c("T999", "T888")", "cols" .
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How to access object attribute given string corresponding to name of that attribute
How do you set/get the values of attributes of t given by m>x m> ?
3 Answers
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Natural Sort Order in C#
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[DllImport("shlwapi.dll", CharSet = CharSet.Unicode)]
private static em>x m>tern int StrCmpLogicalW(string psz1, string psz2);
Michael Kaplan has some em>x m>amples of how this function works here, and the changes that were made for Vista to make it work more intuitively. The plus side of this function...
Struct inheritance in C++
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Yes, struct is em>x m>actly like class em>x m>cept the default accessibility is public for struct (while it's private for class).
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Is == in PHP a case-sensitive string comparison?
...strings, you may wish to normalize them first. See the Normalizer class.
Em>x m>ample (output in UTF-8):
$s1 = mb_convert_encoding("\m>x m>00\m>x m>e9", "UTF-8", "UTF-16BE");
$s2 = mb_convert_encoding("\m>x m>00\m>x m>65\m>x m>03\m>x m>01", "UTF-8", "UTF-16BE");
//look the same:
echo $s1, "\n";
echo $s2, "\n";
var_dump($s1 == $s2);...
Why do I have to access template base class members through the this pointer?
If the classes below were not templates I could simply have m>x m> in the derived class. However, with the code below, I have to use this->m>x m> . Why?
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Dynamically adding properties to an Em>x m>pandoObject
I would like to dynamically add properties to a Em>x m>pandoObject at runtime. So for em>x m>ample to add a string property call NewProp I would like to write something like
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CSS Selector “(A or B) and C”?
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is there a better syntam>x m>?
No. CSS' or operator (,) does not permit groupings. It's essentially the lowest-precedence logical operator in selectors, so you must use .a.c,.b.c.
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Python string.join(list) on object array rather than string array
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You could use a list comprehension or a generator em>x m>pression instead:
', '.join([str(m>x m>) for m>x m> in list]) # list comprehension
', '.join(str(m>x m>) for m>x m> in list) # generator em>x m>pression
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Em>x m>tract elements of list at odd positions
So I want to create a list which is a sublist of some em>x m>isting list.
5 Answers
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