... in the case of low contention that they tested (70% lookups, 20% inserts, 10% deletes); they actually beat the lock-free solution for this scenario when they made their skip list big enough, i.e. going from 200K to 2M elements, so that the probability of contention on any lock became negligible. It...

...oportions between children of a Component (for example, child 1 should use 10% of space, child 2 40%, child 3 50%), is it possible to achieve that without implementing a custom LayoutManager? Any of the Big-Three can, can't even GridBag (never bothered to really master, too much trouble for too li...

...eral things that it does. Why do you assume that the OP only wants to know 10% of the answer? If all of the info is presented, each person can decide how much of it to take. But if only some info is given, then the choice was made for them. I choose to provide as much info as possible because most o...

...5000 iterations you hit your d==0 case. While 50% might not happen often, 10% or 1% could easily happen, or even 90% or 99%. The test as displayed only really tests "if you basically never, ever go down a branch, does branch prediction make removing the branch pointless?", to which the answer is "y...

...这个指标在很多系统中都提及到，比如电信的、金融的、企业资源管理的等等。举个例子，我们楼下的建行，假如每天的业务类别是这样的：20个开户，5个销户，300个存款，500取款，100个汇款等，那么在做他们的营业系统测试时...

...ge Pixel to: struct Pixel { unsigned char r, g, b; }; Result: about 10% faster. Still slower than an array. Hm. # ./vector UseArray completed in 3.239 seconds UseVector completed in 5.567 seconds Idea #4 - Use iterator instead of loop index How about using a vector<Pixel>::iterator...

... slower for remote memory, NUMA accesses slow down your memory accesses by 10%. In addition, if you only have free memory on a single NUMA node, all the processes needing memory on the starved node will be allocated memory from the other node which accesses are more expensive. Even worst, the oper...

.... There's nothing special about halves, though -- if you can only ignore 10% of your input at each step, it's still logarithmic. O(n) - you do some fixed amount of work per input element. (But see below.) O(n log(n)) - there are a few variants. You can divide the input into two piles (in no mor...

...t test under VS, but this seems to be faster than your code for g++, about 10%. It could probably be tuned, the decision values chosen are guesses. int only, sorry. typedef unsigned buf_t; static buf_t * reduce(unsigned val, buf_t * stp) { unsigned above = val / 10000; if (above != 0) ...

... the increased processing, and it performed the same on desktop, and only ~10% faster on mobile. The final optimization technique to apply - unroll the loop. Since we're looping a fixed number of times, we can technically write this all out by hand. I tried this once with a single random variable...