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Joining three tables using MySQL
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Simply use:
select s.name "Student", c.name "Course"
from student s, bridge b, course c
where b.sid = s.sid and b.cid = c.cid
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PostgreSQL DISTINCT ON with different ORDER BY
...expression(s).
Official documentation
So you'll have to add the address_id to the order by.
Alternatively, if you're looking for the full row that contains the most recent purchased product for each address_id and that result sorted by purchased_at then you're trying to solve a greatest N per gr...
Schema for a multilanguage database
...translation table for each translatable table?
CREATE TABLE T_PRODUCT (pr_id int, PRICE NUMBER(18, 2))
CREATE TABLE T_PRODUCT_tr (pr_id INT FK, languagecode varchar, pr_name text, pr_descr text)
This way if you have multiple translatable column it would only require a single join to get it + since...
Checking out Git tag leads to “detached HEAD state”
...ipt for my git project and I just started using tags. I've added a new tag called v2.0 :
2 Answers
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Handling colon in element ID with jQuery
We are not able to access the div element with ID "test: abc" in JS code using jQuery.
9 Answers
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NSDefaultRunLoopMode vs NSRunLoopCommonModes
...p mode, rather than the specific default run loop. The special pseudo-mode called NSRunLoopCommonModes is used by many input sources including event tracking. For example assigning NSURLConnection's instance to the common mode means associates its events to "tracking mode" in addition to the "defaul...
Mysql order by specific ID values
...ible to sort in mysql by "order by" using predefined set of column values (ID) like: order by (ID=1,5,4,3) so I would get record 1, 5, 4, 3 in that order out?
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Rails: Why does find(id) raise an exception in rails? [duplicate]
If there is no user with an id of 1 in the database, trying User.find(1) will raise an exception.
2 Answers
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How to create Temp table with SELECT * INTO tempTable FROM CTE Query
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This doesn't answer the question. The OP specifically asked how to do it with Select Into, and this response does not do that. It's a good answer, but it's not the right answer.
– DaveInAZ
Jan 17 '18 at 17:52
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COUNT(*) vs. COUNT(1) vs. COUNT(pk): which is better? [duplicate]
...ies that need to count everything, even for joins, use *
SELECT boss.boss_id, COUNT(subordinate.*)
FROM boss
LEFT JOIN subordinate on subordinate.boss_id = boss.boss_id
GROUP BY boss.id
But don't use COUNT(*) for LEFT joins, as that will return 1 even if the subordinate table doesn't match anythi...