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My attempt at value initialization is interpreted as a function declaration, and why doesn't A a(())
...has taught me is what is known as the "most vexing parse", which is classically demonstrated with a line such as
5 Answers
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How do I import CSV file into a MySQL table?
... MySQL table so that I can refactor into a sane format. I created a table called 'CSVImport' that has one field for every column of the CSV file. The CSV contains 99 columns , so this was a hard enough task in itself:
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Are there any reasons to use private properties in C#?
...et
{
if (_password == null)
{
_password = CallExpensiveOperation();
}
return _password;
}
}
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Make a link open a new window (not tab) [duplicate]
... @JeanGkol I rewrote my answer to clarify the issue. Technically, it is working, because it opens a new browsing context (like it is supposed to do). The problem is, that in modern browsers "browsing context" is a tab instead of a window (you can change this in the settings though).
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What is the type of lambda when deduced with “auto” in C++11?
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The type of a lambda expression is unspecified.
But they are generally mere syntactic sugar for functors. A lambda is translated directly into a functor. Anything inside the [] are turned into constructor parameters and members of the functor object, and the parameters inside () are turned ...
ADB Shell Input Events
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3 --> "KEYCODE_HOME"
4 --> "KEYCODE_BACK"
5 --> "KEYCODE_CALL"
6 --> "KEYCODE_ENDCALL"
7 --> "KEYCODE_0"
8 --> "KEYCODE_1"
9 --> "KEYCODE_2"
10 --> "KEYCODE_3"
11 --> "KEYCODE_4"
12 --> "KEYCODE_5"
13 --> "KEYCODE_6"
14 --> "KEYCODE_7"
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How do I access command line arguments in Python?
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Python tutorial explains it:
import sys
print(sys.argv)
More specifically, if you run python example.py one two three:
>>> import sys
>>> print(sys.argv)
['example.py', 'one', 'two', 'three']
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How to check if a map contains a key in Go?
...ring) and ok will receive a bool that will be set to true if "foo" was actually present in the map
evaluates ok, which will be true if "foo" was in the map
If "foo" is indeed present in the map, the body of the if statement will be executed and val will be local to that scope.
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How to correctly use the extern keyword in C
...les: on variables it doesn't instantiate the variable itself, i.e. doesn't allocate any memory. This needs to be done somewhere else. Thus it's important if you want to import the variable from somewhere else. For functions, this only tells the compiler that linkage is extern. As this is the default...
*.h or *.hpp for your class definitions
...ss definitions, but after reading some boost library code, I realised they all use *.hpp . I've always had an aversion to that file extension, I think mainly because I'm not used to it.
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