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Cannot use ref or out parameter in lambda expressions
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edited Apr 27 '16 at 9:30
silkfire
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How does type Dynamic work and how to use it?
...> val d = new DynImpl
d: DynImpl = DynImpl@6040af64
scala> d.foo
res37: String = foo
scala> d.bar
res38: String = bar
scala> d.selectDynamic("foo")
res54: String = foo
As one can see, it is also possible to call the dynamic methods explicitly.
updateDynamic
Because updateDynamic i...
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