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Ineligible Devices section appeared in Xcode 6.x.x

...6 my devices moved to greyed-out section Ineligible Devices and I can't select them as deploy target: 32 Answers ...
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How to print from GitHub

... Here's a super simple solution: Simply select all the text in the readme that you want to print, then print and choose "Only selected text". This worked perfectly in Chrome (including images) and required no javascript or external sites or downloading or buildin...
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How to create a self-signed certificate for a domain name for development?

...g the IIS Manager Launch the IIS Manager At the server level, under IIS, select Server Certificates On the right hand side under Actions select Create Self-Signed Certificate Where it says "Specify a friendly name for the certificate" type in an appropriate name for reference. Examples: www.dom...
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How can I make an entire HTML form “readonly”?

...e="text" name="something" placeholder="enter some text" /> <select> <option value="0" disabled="disabled" selected="selected">select somethihng</option> <option value="1">woot</option> <option value="2">is</opt...
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【转】用App Inventor 2实现电子围栏功能 - App应用开发 - 清泛IT社区,为创新赋能!

在行空板《家庭安全相册》项目中,第四部分是手机APP监护人部分。这部分需要完成手机获取家庭成员传送回来的位置后,计算是否在安全的电子围栏范围内。因为电子围栏是相对复杂的部分,因此独立一章详细说明。 App In...
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How to select last two characters of a string

I need to select last two characters from the variable, whether it is digit or letters. 9 Answers ...
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postgresql - replace all instances of a string within text field

...g regex replacment. Let's see how easy it is to replace a cat with a dog. SELECT regexp_replace('Cat bobcat cat cats catfish', 'cat', 'dog'); --> Cat bobdog cat cats catfish SELECT regexp_replace('Cat bobcat cat cats catfish', 'cat', 'dog', 'i'); --> dog...
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The project cannot be built until the build path errors are resolved.

...ng Project > Clean... from the menu? This will force a new build on the selected projects in Eclipse. share | improve this answer | follow | ...
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LINQ - Left Join, Group By, and Count

...into j1 from j2 in j1.DefaultIfEmpty() group j2 by p.ParentId into grouped select new { ParentId = grouped.Key, Count = grouped.Count(t=>t.ChildId != null) } share | improve this answer ...
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Create code first, many to many, with additional fields in association table

...OfMembers = context.Members .Where(m => m.LastName == "Smith") .SelectMany(m => m.MemberComments.Select(mc => mc.Comment)) .ToList(); ... or ... var commentsOfMembers = context.MemberComments .Where(mc => mc.Member.LastName == "Smith") .Select(mc => mc.Comment) ...