大约有 5,000 项符合查询结果(耗时:0.0147秒) [XML]

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JSON: why are forward slashes escaped?

... JSON doesn't require you to do that, it allows you to do that. It also allows you to use "\u0061" for "A", but it's not required. Allowing \/ helps when embedding JSON in a <script> tag, which doesn't allow </ inside...
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Maven: missing net.sf.json-lib

I found net.sf.json-lib in the central repository . Copy-pasted the dependency (with version 2.3), and then when I build I get this error: ...
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How to use the 'main' parameter in package.json?

...dy. However, still having doubts about the 'main' parameter in the package.json of a Node project. 7 Answers ...
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Making a property deserialize but not serialize with json.net

...me configuration files which were generated by serializing C# objects with Json.net. 10 Answers ...
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Passing A List Of Objects Into An MVC Controller Method Using jQuery Ajax

... Using NickW's suggestion, I was able to get this working using things = JSON.stringify({ 'things': things }); Here is the complete code. $(document).ready(function () { var things = [ { id: 1, color: 'yellow' }, { id: 2, color: 'blue' }, { id: 3, color: 'red' } ];...
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JAX-RS — How to return JSON and HTTP status code together?

...ST web app (NetBeans 6.9, JAX-RS, TopLink Essentials) and trying to return JSON and HTTP status code. I have code ready and working that returns JSON when the HTTP GET method is called from the client. Essentially: ...
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How do I deserialize a JSON string into an NSDictionary? (For iOS 5+)

In my iOS 5 app, I have an NSString that contains a JSON string. I would like to deserialize that JSON string representation into a native NSDictionary object. ...
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MongoDB副本集详解 优于以往的主从模式 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术

MongoDB副本集详解 优于以往的主从模式因为MongoDB使用内存映射文件,所以必须使用64位版本。官方下载地址如下:http: www mongodb org downloads实验环境使用的Mongodb版本为mon 因为MongoDB使用内存映射文件,所以必须使用64位版本。 官方...
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How to auto-generate a C# class file from a JSON string [closed]

Given the following JSON object, 3 Answers 3 ...
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How to use getJSON, sending data with post method?

... The $.getJSON() method does an HTTP GET and not POST. You need to use $.post() $.post(url, dataToBeSent, function(data, textStatus) { //data contains the JSON object //textStatus contains the status: success, error, etc }, "json...