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Putting a simple if-then-else statement on one line [duplicate]
I'm just getting into Python and I really like the terseness of the syntax. However, is there an easier way of writing an if - then - else statement so it fits on one line?
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Pythonic way to print list items
I would like to know if there is a better way to print all objects in a Python list than this :
11 Answers
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How to find reason of failed Build without any error or warning
I have a WebApplication which contains reference to WCF services.
33 Answers
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Unzipping files in Python
I read through the zipfile documentation , but couldn't understand how to unzip a file, only how to zip a file. How do I unzip all the contents of a zip file into the same directory?
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Where to define custom error types in Ruby and/or Rails?
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5 Answers
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mkdir's “-p” option
...e a terribly complicated question I have, but it's one I can't find the answer to. I'm confused about what the -p option does in Unix. I used it for a lab assignment while creating a subdirectory and then another subdirectory within that one. It looked like this:
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_=> what does this underscore mean in Lambda expressions?
What does an lambda expression like _=> expr mean?
5 Answers
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Java: Integer equals vs. ==
As of Java 1.5, you can pretty much interchange Integer with int in many situations.
7 Answers
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Restore file from old commit in git
I have an old commit that I did a few weeks ago. I want to restore only a single file from that commit. What do I do?
4 Ans...
how to debug the js in jsfiddle
I am looking at this jsfiddle: http://jsfiddle.net/carpasse/mcVfK/
It works fine that is not the problem , I just want to know how to debug through the javascript. I tried to use the debugger command and I cant find it in the sources tab?
any idea how I can debug this?
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