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PHP array_filter with arguments
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I am not a php savy, so maybe this is an obvious question, but how can you pass in an array to array_filter and still make it work? the documentation never talks about this, except for someone's comment.
– Nicola P...
How to change the session timeout in PHP?
I would like to extend the session timeout in php
7 Answers
7
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Redirect all to index.php using htaccess
I'm writing a simple PHP-based MVC-ish framework. I want this framework to be able to be installed in any directory.
7 Answ...
How to calculate the difference between two dates using PHP?
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Use this for legacy code (PHP < 5.3). For up to date solution see jurka's answer below
You can use strtotime() to convert two dates to unix time and then calculate the number of seconds between them. From this it's rather easy to calculate differ...
Linux 进程卡住了怎么办？ - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...rocess在我们使用 Linux 系统时，如果网络或者磁盘等 I O 出问题，会发现进程卡住了，即使用 kill -9 也无法杀掉进程，很多常用的调试工具，比如 strace, pstack 等也都失灵了
在我们使用 Linux 系统时，如果网络或者磁盘等 I/O 出...
Accurate way to measure execution times of php scripts
I want to know how many milliseconds a PHP for-loop takes to execute.
14 Answers
14
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动态追踪（Dynamic Tracing）技术漫谈 - 操作系统(内核) - 清泛网 - 专注C/C++及内核技术
...在非常短的时间内，回答一些很难的关于软件系统方面的问题，从而更快速地排查和解决问题。它兴起和繁荣的一个大背景是，我们正处在一个快速增长的互联网时代，作为工程师，面临着两大方面的挑战：一是规模，不管是用...
How do I pass parameters into a PHP script through a webpage?
I am calling a PHP script whenever a webpage loads. However, there is a parameter that the PHP script needs to run (which I normally pass through the command line when I am testing the script).
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Check if PHP session has already started
I have a PHP file that is sometimes called from a page that has started a session and sometimes from a page that doesn't have session started. Therefore when I have session_start() on this script I sometimes get the error message for "session already started". For that I've put these lines:
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How do I create a copy of an object in PHP?
It appears that in PHP objects are passed by reference. Even assignment operators do not appear to be creating a copy of the Object.
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