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Convert floats to ints in Pandas?
...nge(5), columns=['a'])
df.a = df.a.astype(float)
df
Out[33]:
a
0 0.0000000
1 1.0000000
2 2.0000000
3 3.0000000
4 4.0000000
pd.options.display.float_format = '{:,.0f}'.format
df
Out[35]:
a
0 0
1 1
2 2
3 3
4 4
...
How to compare software version number using js? (only number)
...at if we have version strings that are not made up of just digits (e.g. "1.0a")?
What should happen if one version string has more parts than the other? Most likely "1.0" should be considered less than "1.0.1", but what about "1.0.0"?
Here's the code for an implementation that you can use directly...
How to profile a bash shell script slow startup?
... you'd like to begin a trace in any Bash script):
PS4='+ $(date "+%s.%N")\011 '
exec 3>&2 2>/tmp/bashstart.$$.log
set -x
add
set +x
exec 2>&3 3>&-
at the end of ~/.bashrc (or at the end of the section of any Bash script you'd like tracing to stop). The \011 is an octal ...
How to randomize (or permute) a dataframe rowwise and columnwise?
...
Given the R data.frame:
> df1
a b c
1 1 1 0
2 1 0 0
3 0 1 0
4 0 0 0
Shuffle row-wise:
> df2 <- df1[sample(nrow(df1)),]
> df2
a b c
3 0 1 0
4 0 0 0
2 1 0 0
1 1 1 0
By default sample() randomly reorders the elements passed as the first argument. This m...
What is the difference between NULL, '\0' and 0?
...ear to be differences between various values of zero -- NULL , NUL and 0 .
11 Answers
...
Are +0 and -0 the same?
Reading through the ECMAScript 5.1 specification , +0 and -0 are distinguished.
9 Answers
...
Difference between break and continue statement
...
answered Jan 20 '09 at 18:02
Xn0vv3rXn0vv3r
16.4k1313 gold badges5353 silver badges6363 bronze badges
...
How do I measure separate CPU core usage for a process?
...
Bojin Li
5,51322 gold badges2020 silver badges3333 bronze badges
answered Oct 11 '10 at 21:45
abdollarabdollar
...
C#位运算符(C#按位与、按位或 等) - 更多技术 - 清泛网 - 专注C/C++及内核技术
...算按位对运算对象的值进行非运算,即:如果某一位等于0,就将其转变为1;如果某一位等于1,就将其转变为0。
比如,对二进制的10010001进行位逻辑非运算,结果等于01101110,用十进制表示就是:
~145等于110;对二进制的01010101...
Adding a column to a data.frame
...p <- as.factor(your.df$group)
no h_freq h_freqsq group
1 1 0.40998238 0.06463876 1
2 2 0.98086928 0.33093795 1
3 3 0.28908651 0.74077119 1
4 4 0.10476768 0.56784786 1
5 1 0.75478995 0.60479945 2
6 2 0.26974011 0.95231761 2
7 3 0.53676266 0.74370154...