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Switching between Android Navigation Drawer image and Up caret when using fragments
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Yout should also lock the swipe gesture for the navigation drawer in arrow mode: mDrawerLayout.setDrawerLockMode(DrawerLayout.LOCK_MODE_LOCKED_CLOSED); and enable it again in drawer indicator mode
– artkoenig
Jun 11 '14 at 1...
How to change the font on the TextView?
... these tools is essential to help users
quickly understand a screen of information. To support such use of
typography, Ice Cream Sandwich introduced a new type family named
Roboto, created specifically for the requirements of UI and
high-resolution screens.
The current TextView framewor...
How can I get stock quotes using Google Finance API?
I'm looking for access to financial data from Google services.
13 Answers
13
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How to play audio?
... edited Feb 15 at 16:55
Learn for Fun
67933 silver badges1515 bronze badges
answered Sep 5 '13 at 5:03
UriUr...
Producing a new line in XSLT
I want to produce a newline for text output in XSLT. Any ideas?
12 Answers
12
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How to read a local text file?
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You need to check for status 0 (as when loading files locally with XMLHttpRequest, you don't get a status returned because it's not from a Webserver)
function readTextFile(file)
{
var rawFile = new XMLHttpRequest();
rawFile.open("GET"...
Lua简明教程 - 脚本技术 - 清泛IT论坛，有思想、有深度
...另外，条件表达式中的与或非为分是：and, or, not关键字。for 循环
sum = 0
for i = 1, 100 do
sum = sum + i
end复制代码
从1到100的奇数和
sum = 0
for i = 1, 100, 2 do
sum = sum + i
end复制代码
从100到1的偶数和
sum = 0
for i = 100, 1...
Changing iframe src with Javascript
...to change an <iframe src=... > when someone clicks a radio button. For some reason my code is not working correctly and I am having trouble figuring out why. Here is what I have:
...
Javascript How to define multiple variables on a single line?
... "So while you can get away with multiple right hand assignments for things like numeric literals"
– meder omuraliev
Nov 12 '10 at 16:32
1
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Javascript - sort array based on another array
..., 'b']
]
sorting = [ 'b', 'c', 'b', 'b', 'c', 'd' ];
result = []
sorting.forEach(function(key) {
var found = false;
items = items.filter(function(item) {
if(!found && item[1] == key) {
result.push(item);
found = true;
return false;
...