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How to add a new method to a php object on the fly?
...ure, I'm not saying I'm an expert at extending an object during runtime in PHP, but I honestly can't say I see much wrong with it. (maybe I just have poor taste)
– karim79
May 30 '10 at 9:13
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Facebook API - How do I get a Facebook user's profile image through the Facebook API (without requir
...m/users_unique_url ). How can I accomplish this? Is there a Faceboook API call that fetches a user's profile image URL without the user needing to Allow the application?
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how to bypass Access-Control-Allow-Origin?
I'm doing a ajax call to my own server on a platform which they set prevent these ajax calls (but I need it to fetch the data from my server to display retrieved data from my server's database).
My ajax script is working , it can send the data over to my server's php script to allow it to process.
H...
How to find out where a function is defined?
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@EHerman I don't think you can find callers of a function with reflection. If you could it probably wouldn't work well for this because PHP files tend to be included on demand, and so you would likely not have all the code loaded which does call the function.
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Get the Query Executed in Laravel 3/4
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Laravel 4+
In Laravel 4 and later, you have to call DB::getQueryLog() to get all ran queries.
$queries = DB::getQueryLog();
$last_query = end($queries);
Or you can download a profiler package. I'd recommend barryvdh/laravel-debugbar, which is pretty neat. You can read f...
File Upload without Form
... using jQuery. The input tag is not inside any form tag. It stands individually. So I don't want to use jQuery plugins like 'ajaxForm' or 'ajaxSubmit'.
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Passing an Array as Arguments, not an Array, in PHP
...dard func($arg1, $arg2) manner. But now I'm lost on how to do it. I recall the manner of passing by reference, how to "glob" incoming parameters ... but not how to de-list the array into a list of arguments.
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PHP: How to generate a random, unique, alphanumeric string for use in a secret link?
...of an application. In particular, rand() and uniqid() are not cryptographically secure random number generators. See Scott's answer for a secure alternative.
If you do not need it to be absolutely unique over time:
md5(uniqid(rand(), true))
Otherwise (given you have already determined a unique l...
Win32 创建控件风格不是Win XP的解决方案 - C/C++ - 清泛网 - 专注C/C++及内核技术
...="x86"，如果这个应用程序想在x64下面运行，就会导致一个问题：这个64位的程序链接的是32位的comctl32库，创建控件就会失败。所以最好的解决方案就是下面这种做法：
在头文件里面加入下面的语句：
#ifdef _UNICODE
#if defined _M_I...
可重入函数、不可重入函数及线程安全 - C/C++ - 清泛网 - 专注C/C++及内核技术
...区，中断向量表等，所以它如果被中断的话，可能会出现问题，这类函数是不能运行在多任务环境下的。
可重入函数也可以这样理解，重入即表示重复进入，首先它意味着这个函数可以被中断，其次意味着它除了使用自己栈上...