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How can I get form data with JavaScript/jQuery?
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$('form').serialize() //this produces: "foo=1&bar=xxx&this=hi"
demo
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Best way to use multiple SSH private keys on one client
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ssh-add ~/.ssh/xxx_id_rsa
Make sure you test it before adding with:
ssh -i ~/.ssh/xxx_id_rsa username@example.com
If you have any problems with errors sometimes changing the security of the file helps:
chmod 0600 ~/.ssh/xxx_id_rsa
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App Inventor 2 UrsPahoMqttClient 拓展 - 物联网轻量级MQTT协议 · App Inventor 2 中文网
...们 关注我，不迷路 在线 客服 扫码添加客服咨询 我要 分享 扫码分享到朋友圈 顶部 var qrcode = new QRCode("qrcode", { ...
Bootstrap 3 breakpoints and media queries
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Dave Powers
1,23322 gold badges1919 silver badges2525 bronze badges
answered Feb 25 '14 at 8:33
Antonio EspinosaAntonio Espinosa
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Does Ruby regular expression have a not match operator like “!~” in Perl?
...match operator just like !~ in perl. I feel it's inconvenient to use (?!xxx) or (?<!xxxx) because you cannot use regex patterns in the xxx part.
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Does IMDB provide an API? [closed]
... @OptimusCrime I had an issue the other day with IP's from the 85.XXX.XXX.XXX range and had to temporarily block ALL of them until I could get things under control. Sadly this is one of the trade-offs I have to deal with by not requiring API keys, people tend to just abuse the hell out of i...
How do I use boolean variables in Perl?
...onsistent with your longer explanation. Consider: my $value = do { package XXX; use overload q[""] => sub { "XXX" }, q[bool] => sub { 0 }; bless [] };. Now $value will stringify to "XXX" but boolifies to false.
– tobyink
Feb 25 '14 at 15:17
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How can I concatenate regex literals in JavaScript?
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I don't quite agree with the "eval" option.
var xxx = /abcd/;
var yyy = /efgh/;
var zzz = new RegExp(eval(xxx)+eval(yyy));
will give "//abcd//efgh//" which is not the intended result.
Using source like
var zzz = new RegExp(xxx.source+yyy.source);
will give "/abcdefgh...
SQL Query Where Field DOES NOT Contain $x
...rent - your question isn't totally clear so pick which one to use. LIKE 'xxx%' can use an index. LIKE '%xxx' or LIKE '%xxx%' can't.
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How to replace an entire line in a text file by line number
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in bash, replace N,M by the line numbers and xxx yyy by what you want
i=1
while read line;do
if((i==N));then
echo 'xxx'
elif((i==M));then
echo 'yyy'
else
echo "$line"
fi
((i++))
done < orig-file > new-file
EDIT
In fact in this solution t...