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UML class diagram enum
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And then just have an association between that and your class.
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Run function from the command line
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With the -c (command) argument (assuming your file is named foo.py):
$ python -c 'import foo; print foo.hello()'
Alternatively, if you don't care about namespace pollution:
$ python -c 'from foo import *; print hello()'
And the middle g...
How to determine the version of the C++ standard used by the compiler?
How do you determine what version of the C++ standard is implemented by your compiler? As far as I know, below are the standards I've known:
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How to sort a list of objects based on an attribute of the objects?
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No problem. btw, if muhuk is right and it's a list of Django objects, you should consider his solution. However, for the general case of sorting objects, my solution is probably best practice.
– Triptych
Dec 31 '08 at 17:...
Is the list of Python reserved words and builtins available in a library?
Is the list of Python reserved words and builtins available in a library? I want to do something like:
1 Answer
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What's the difference between a Python module and a Python package?
What's the difference between a Python module and a Python package?
5 Answers
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How do I use a Boolean in Python?
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Actually Python didn't have a boolean type for a long time (as in old C), and some programmers still use integers instead of booleans.
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Why aren't python nested functions called closures?
I have seen and used nested functions in Python, and they match the definition of a closure. So why are they called nested functions instead of closures ?
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Get class that defined method
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classes = list(c.__bases__) + classes
return None
And the Example:
>>> class A(object):
... def test(self): pass
>>> class B(A): pass
>>> class C(B): pass
>>> class D(A):
... def test(self): print 1
>>> class E(D,C): pass...
Django filter queryset __in for *every* item in list
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Summary:
One option is, as suggested by jpic and sgallen in the comments, to add .filter() for each category. Each additional filter adds more joins, which should not be a problem for small set of categories.
There is the aggregation approach. This query would be short...