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Hash function that produces short hashes?
...e a way of encryption that can take a string of any length and produce a sub-10-character hash? I want to produce reasonably unique ID's but based on message contents, rather than randomly.
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How to convert an int to a hex string?
I want to take an integer (that will be
13 Answers
13
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When & why to use delegates? [duplicate]
... use Delegates appropriately .
they are widely used in events declaration, but when should I use them in my own code and why are they useful? why not to use something else?
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Is there any connection string parser in C#?
I have a connection string and I want to be able to peek out for example "Data Source".
Is there a parser, or do I have to search the string?
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jQuery table sort
I have a very simple HTML table with 4 columns:
15 Answers
15
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Oracle: how to UPSERT (update or insert into a table?)
The UPSERT operation either updates or inserts a row in a table, depending if the table already has a row that matches the data:
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Fastest way to convert JavaScript NodeList to Array?
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The second one tends to be faster in some browsers, but the main point is that you have to use it because the first one is just not cross-browser. Even though The Times They Are a-Changin'
@kangax (IE 9 preview)
Array.prototype.slice can now co...
How to compare if two structs, slices or maps are equal?
...qual, or you can implement your own function (which performance wise would be better than using reflection):
http://play.golang.org/p/CPdfsYGNy_
m1 := map[string]int{
"a":1,
"b":2,
}
m2 := map[string]int{
"a":1,
"b":2,
}
fmt.Println(reflect.DeepEqual(m1, m2))
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Set multiple properties in a List ForEach()?
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All you need to do is introduce some brackets so that your anonymous method can support multiple lines:
list.ForEach(i => { i.a = "hello!"; i.b = 99; });
share
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Add regression line equation and R^2 on graph
...5XMA
lm_eqn <- function(df){
m <- lm(y ~ x, df);
eq <- substitute(italic(y) == a + b %.% italic(x)*","~~italic(r)^2~"="~r2,
list(a = format(unname(coef(m)[1]), digits = 2),
b = format(unname(coef(m)[2]), digits = 2),
r2 = format(summary(m)$r.squ...
