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Django import error - no module named django.conf.urls.defaults
...to
from django.conf.urls import patterns, url, include
However, in your case the problem is in a third party app, graphite. The issue has been fixed in graphite's master branch and version 0.9.14+.
In Django 1.8+ you can remove patterns from the import, and use a list of url()s instead.
from dj...
Turning off “created by” stamp when generating files in IntelliJ
I can't find an option for this. For example, when I create a new Scala class, this text is placed in the file:
5 Answers
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How do I get and set Environment variables in C#?
How can I get Environnment variables and if something is missing, set the value?
6 Answers
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RegEx backreferences in IntelliJ
... me it works only if I explicitly surround my group with "()", otherwise I can't reference it later. Ex: search (foo) replace: $1bar
– Ghedeon
Nov 17 '15 at 15:41
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How to use ? : if statements with Razor and inline code blocks
...strange to use the paren rather then the brace
– pat capozzi
Oct 1 '17 at 17:03
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How do I negate a condition in PowerShell?
...e:
if (-Not (Test-Path C:\Code)) {
write "it doesn't exist!"
}
You can also use !: if (!(Test-Path C:\Code)){}
Just for fun, you could also use bitwise exclusive or, though it's not the most readable/understandable method.
if ((test-path C:\code) -bxor 1) {write "it doesn't exist!"}
...
Does svn have a `revert-all` command?
...R .
This will not delete any new file not under version control. But you can easily write a shell script to do that like:
for file in `svn status|grep "^ *?"|sed -e 's/^ *? *//'`; do rm $file ; done
share
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Cannot get to $rootScope
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You can not ask for instance during configuration phase - you can ask only for providers.
var app = angular.module('modx', []);
// configure stuff
app.config(function($routeProvider, $locationProvider) {
// you can inject any...
Foreign key from one app into another in Django
...second attempt should work:
To refer to models defined in another application, you must instead explicitly specify the application label. For example, if the Manufacturer model above is defined in another application called production, you'd need to use:
class Car(models.Model):
manufactur...
Scala equivalent of Java java.lang.Class Object
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According to "The Scala Type System",
val c = new C
val clazz = c.getClass // method from java.lang.Object
val clazz2 = classOf[C] // Scala method: classOf[C] ~ C.class
val methods = clazz.getMethods // method from...