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How to break/exit from a each() function in JQuery? [duplicate]

... According to the documentation you can simply return false; to break: $(xml).find("strengths").each(function() { if (iWantToBreak) return false; }); share | improve this answe...
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How to get the URL without any parameters in JavaScript?

... lonesomedaylonesomeday 207k4545 gold badges296296 silver badges306306 bronze badges ...
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Iterate a list as pair (current, next) in Python

I sometimes need to iterate a list in Python looking at the "current" element and the "next" element. I have, till now, done so with code like: ...
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How can I sanitize user input with PHP?

Is there a catchall function somewhere that works well for sanitizing user input for SQL injection and XSS attacks, while still allowing certain types of HTML tags? ...
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How do sessions work in Express.js with Node.js?

...g Express.js , sessions are dead simple. I'm curious how they actually work though. 4 Answers ...
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ScalaTest in sbt: is there a way to run a single test without tags?

I know that a single test can be ran by running, in sbt, 5 Answers 5 ...
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Inline SVG in CSS

... Yes, it is possible. Try this: body { background-image: url("data:image/svg+xml;utf8,<svg xmlns='http://www.w3.org/2000/svg' width='10' height='10'><linearGradient id='gradient'><stop offset='10%' stop-color='%23F00'/><stop offset='90%'...
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How to dynamically change a web page's title?

... that implements a set of tabs each showing different content. The tab clicks do not refresh the page but hide/unhide contents at the client side. ...
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How to manage startActivityForResult on Android?

...TIVITY); In your SecondActivity set the data which you want to return back to FirstActivity. If you don't want to return back, don't set any. For example: In SecondActivity if you want to send back data: Intent returnIntent = new Intent(); returnIntent.putExtra("result",result); setResult(Activi...
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Cannot find JavaScriptSerializer in .Net 4.0

... Check if you included the .net 4 version of System.Web.Extensions - there's a 3.5 version as well, but I don't think that one works. These steps work for me: Create a new console application Change the target to .net 4 instead...