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NameError: name 'self' is not defined
...y if you try to reference values for that object inside the function.
def foo():
print(self.bar)
>NameError: name 'self' is not defined
def foo(self):
print(self.bar)
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What is the correct answer for cout
...r<<(std::operator<<(std::cout, a++), a);
C++ guarantees that all side effects of previous evaluations will have been performed at sequence points. There are no sequence points in between function arguments evaluation which means that argument a can be evaluated before argument std::ope...
I need to get all the cookies from the browser
I need to get all the cookies stored in my browser using JavaScript. How can it be done?
9 Answers
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HEAD and ORIG_HEAD in Git
..., and it is a commit on top of which "git commit" would make a new one. Usually HEAD is symbolic reference to some other named branch; this branch is currently checked out branch, or current branch. HEAD can also point directly to a commit; this state is called "detached HEAD", and can be understood...
How do I tell CPAN to install all dependencies?
How do I tell CPAN to install all dependencies?
10 Answers
10
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How to pass anonymous types as parameters?
... (when extracting data) is to also pass a selector - i.e. something like:
Foo<TSource, TValue>(IEnumerable<TSource> source,
Func<TSource,string> name) {
foreach(TSource item in source) Console.WriteLine(name(item));
}
...
Foo(query, x=>x.Title);
...
How to get “their” changes in the middle of conflicting Git rebase?
...
You want to use:
git checkout --ours foo/bar.java
git add foo/bar.java
If you rebase a branch feature_x against master (i.e. running git rebase master while on branch feature_x), during rebasing ours refers to master and theirs to feature_x.
As pointed out in...
How to allow only one radio button to be checked?
...
OMG... well, if I dont assign names to them. they all should have empty string as name by default right? Thank you
– Clinteney Hui
Mar 24 '11 at 12:58
20
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Rails Console: reload! not reflecting changes in model files? What could be possible reason?
... method on an object. Eg, if you change the definition of the class method foo(), then in the console a.foo will not use the new definition unless you first reload a.
– jpw
Jun 12 '13 at 0:29
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How to specialize std::hash::operator() for user-defined type in unordered containers?
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You are expressly allowed and encouraged to add specializations to namespace std*. The correct (and basically only) way to add a hash function is this:
namespace std {
template <> struct hash<Foo>
{
size_t operator()(const...