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How to parse JSON in Scala using standard Scala classes?
I am using the build in JSON class in Scala 2.8 to parse JSON code. I don't want to use the Liftweb one or any other due to minimizing dependencies.
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How can I safely encode a string in Java to use as a filename?
I'm receiving a string from an external process. I want to use that String to make a filename, and then write to that file. Here's my code snippet to do this:
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Is there an AddRange equivalent for a HashSet in C#
With a list you can do:
2 Answers
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iPhone - Get Position of UIView within entire UIWindow
The position of a UIView can obviously be determined by view.center or view.frame etc. but this only returns the position of the UIView in relation to it's immediate superview.
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How do I test if a string is empty in Objective-C?
How do I test if an NSString is empty in Objective-C?
30 Answers
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In Python, how do I create a string of n characters in one line of code?
I need to generate a string with n characters in Python. Is there a one line answer to achieve this with the existing Python library? For instance, I need a string of 10 letters:
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Deserializing JSON Object Array with Json.net
I am attempt to use an API that use the follow example structure for their returned json
5 Answers
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Split a string by a delimiter in python
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3 Answers
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Why should I prefer single 'await Task.WhenAll' over multiple awaits?
In case I do not care about the order of task completion and just need them all to complete, should I still use await Task.WhenAll instead of multiple await ? e.g, is DoWork2 below a preferred method to DoWork1 (and why?):
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How to write multiple line property value using PropertiesConfiguration?
I have a properties file with a property with a List value (comma separated), how to write this property in a multi-line ? (backslash after the comma)?
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