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What is the difference between Gemfile and Gemfile.lock in Ruby on Rails
...ndler records the exact versions that were installed. This way, when the sam>me m> library/project is loaded on another machine, running bundle install will look at the Gemfile.lock and install the exact sam>me m> versions, rather than just using the Gemfile and installing the most recent versions. (Running d...
Hidden features of Perl?
What are som>me m> really useful but esoteric language features in Perl that you've actually been able to employ to do useful work?
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Is the 'override' keyword just a check for a overridden virtual m>me m>thod?
...11 is nothing more than a check to make sure that the function being implem>me m>nted is the override ing of a virtual function in the base class.
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Why is rbindlist “better” than rbind?
I am going through docum>me m>ntation of data.table and also noticed from som>me m> of the conversations over here on SO that rbindlist is supposed to be better than rbind .
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What is the most efficient/elegant way to parse a flat table into a tree?
Assum>me m> you have a flat table that stores an ordered tree hierarchy:
14 Answers
14
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Python : List of dict, if exists increm>me m>nt a dict value, if not append a new dict
I would like do som>me m>thing like that.
6 Answers
6
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Force LF eol in git repo and working copy
...oped on Windows, and I wasn't too careful about line endings. When I perform>me m>d the initial commit, I also didn't have any git configuration in place to enforce correct line endings. The upshot is that I have a number of files with CRLF line endings in my github repository.
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Why is access to the path denied?
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According to File.Delete m>Me m>thod...
An UnauthorizedAccessException m>me m>ans one of 4 things:
The caller does not have the required permission.
The file is an executable file that is in use.
Path is a directory.
Path specified a read-only file.
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Simple logical operators in Bash
... commands are executed in a separate subprocess, so any redirection, assignm>me m>nt, etc. perform>me m>d inside the parentheses has no effect outside the parentheses.
With a leading dollar sign, $(…) is a command substitution: there is a command inside the parentheses, and the output from the command is ...
bool operator ++ and --
Today while writing som>me m> Visual C++ code I have com>me m> across som>me m>thing which has surprised m>me m>. It seems C++ supports ++ (increm>me m>nt) for bool, but not -- (decrem>me m>nt). It this just a random decision, or there is som>me m> reason behind this?
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