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How to send a JSON object using html form data
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Get complete form data as array and json stringify it.
var formData = JSON.stringify($("#myForm").serializeArray());
You can use it later in ajax. Or if you are not using ajax; put it in hidden textarea and pass to server. If this data is passed as json stri...
Find unused npm packages in package.json
Is there a way to determine if you have packages in your package.json file that are no longer needed?
6 Answers
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How do I add comments to package.json for npm install?
I've got a simple package.json file and I want to add a comment. Is there a way to do this, or are there any hacks to make this work?
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How to convert xml into array in php?
... = simplexml_load_string($xmlstring, "SimpleXMLElement", LIBXML_NOCDATA);
$json = json_encode($xml);
$array = json_decode($json,TRUE);
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parsing JSONP $http.jsonp() response in angular.js
I am using angular's $http.jsonp() request which is successfully returning json wrapped in a function:
8 Answers
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端侧AI（OnDeviceAI）使用指导 · App Inventor 2 中文网
...代码中的名称重命名。
根据下面的业务说明准备素材、JSON 或系统目标。案例中的按钮代表分步操作，先等初始化、加载或创建成功，再执行下一步。
接住完成事件与错误事件，将原始 JSON 或错误显示在标签。先确认原始结...
JSON.net: how to deserialize without using the default constructor?
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Json.Net prefers to use the default (parameterless) constructor on an object if there is one. If there are multiple constructors and you want Json.Net to use a non-default one, then you can add the [JsonConstructor] attribut...
Add new attribute (element) to JSON object using JavaScript
How do I add new attribute (element) to JSON object using JavaScript?
10 Answers
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How do I convert an object to an array?
...mensional arrays
A somewhat dirty method is to use PHP >= 5.2's native JSON functions to encode to JSON and then decode back to an array. This will not include private and protected members, however, and is not suitable for objects that contain data that cannot be JSON encoded (such as binary d...
RestSharp JSON Parameter Posting
... serialize the body yourself. Just do
request.RequestFormat = DataFormat.Json;
request.AddBody(new { A = "foo", B = "bar" }); // uses JsonSerializer
If you just want POST params instead (which would still map to your model and is a lot more efficient since there's no serialization to JSON) do th...