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How to only get file name with Linux 'find'?
I'm using find to all files in directory, so I get a list of paths. However, I need only file names. i.e. I get ./dir1/dir2/file.txt and I want to get file.txt
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sed: print only matching group
I want to grab the last two numbers (one int, one float; followed by optional whitespace) and print only them.
5 Answers
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How exactly does __attribute__((constructor)) work?
It seems pretty clear that it is supposed to set things up.
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Find the PID of a process that uses a port on Windows
My service crash on startup with the classic:
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Check if a value exists in ArrayList
How can I check if a value that is written in scanner exists in an ArrayList ?
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How to move certain commits to be based on another branch in git?
The situation:
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View a list of recent documents in Vim
Is there a way to view the list of recent documents you've opened in Vim? I realize I could view the cursor jump list, :ju , and then go to a cursor position in the list but this is not ideal because there will be multiple listings of the same document in the list. Is there another command which wo...
Build an ASCII chart of the most commonly used words in a given text [closed]
Build an ASCII chart of the most commonly used words in a given text.
59 Answers
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Capturing Groups From a Grep RegEx
I've got this little script in sh (Mac OSX 10.6) to look through an array of files. Google has stopped being helpful at this point:
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Find running median from a stream of integers
Solution I have read: We can use a max heap on left side to represent elements that are less than the effective median, and a min heap on right side to represent elements that are greater than the effective median.
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