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How can I maintain fragment state when added to the back stack?

I've written up a dummy activity that switches between two fragments. When you go from FragmentA to FragmentB, FragmentA gets added to the back stack. However, when I return to FragmentA (by pressing back), a totally new FragmentA is created and the state it was in is lost. I get the feeling I'm ...
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How do I change the background color of a plot made with ggplot2

By default, ggplot2 produces plots with a grey background. How do I change the color of the background of the plot? 3 Answ...
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Using braces with dynamic variable names in PHP

I'm trying to use dynamic variable names (I'm not sure what they're actually called) But pretty much like this: 8 Answers ...
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What is a “cache-friendly” code?

What is the difference between " cache unfriendly code " and the " cache friendly " code? 9 Answers ...
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How can I access “static” class variables within class methods in Python?

... Instead of bar use self.bar or Foo.bar. Assigning to Foo.bar will create a static variable, and assigning to self.bar will create an instance variable. share ...
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How to add external library in IntelliJ IDEA?

I am trying to add external library (places it in the /libs directory) to my project. When I try to use the methods from that library, I see that they are in red color which means that the library is not recognized. When I click Ctrl+B, I get a message "Cannot find declaration to go to". ...
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Writing a Python list of lists to a csv file

... Python's built-in CSV module can handle this easily: import csv with open("output.csv", "wb") as f: writer = csv.writer(f) writer.writerows(a) This assumes your list is defined as a, as it is in your question. You can twea...
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How to convert a String into an ArrayList?

In my String, I can have an arbitrary number of words which are comma separated. I wanted each word added into an ArrayList. E.g.: ...
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What is the proper way to check for existence of variable in an EJS template (using ExpressJS)?

On the EJS github page, there is one and only one simple example: https://github.com/visionmedia/ejs 13 Answers ...
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How to convert a char to a String?

... string concatenation works as a shortcut as well: String s = "" + 's'; But this compiles down to: String s = new StringBuilder().append("").append('s').toString(); which is less efficient because the StringBuilder is backed by a char[] (over-allocated by StringBuilder() to 16), only for that ...