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Abandoning changes without deleting from history
There is a commit that just didn't work, so I want to abandon it without deleting it from history .
9 Answers
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How do I split a string by a multi-character delimiter in C#?
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http://msdn.microsoft.com/en-us/library/system.string.split.aspx
Example from the docs:
string source = "[stop]ONE[stop][stop]TWO[stop][stop][stop]THREE[stop][stop]";
string[] stringSeparators = new string[] {"[stop]"};
string[] result;
// ...
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Getting key with maximum value in dictionary?
...36, 80: 10, 81: 23, 82: 111, 83: 111, 84: 10, 85: 10, 86: 31, 87: 31,
88: 18, 89: 31, 90: 18, 91: 93, 92: 18, 93: 18, 94: 106, 95: 106, 96: 13, 9232: 35,
98: 26, 99: 26, 100: 26, 101: 26, 103: 88, 104: 13, 106: 13, 107: 101, 1132: 63,
2158: 51, 112: 21, 113: 13, 116: 21, 118: 34, 119:...
Number of days between two NSDates [duplicate]
...tartDate:&toDate
interval:NULL forDate:toDateTime];
NSDateComponents *difference = [calendar components:NSCalendarUnitDay
fromDate:fromDate toDate:toDate options:0];
return [difference day];
}
EDIT:
Fantastic solution above, here's Swift version below as an extension...
.NET - Get protocol, host, and port
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The following (C#) code should do the trick
Uri uri = new Uri("http://www.mywebsite.com:80/pages/page1.aspx");
string requested = uri.Scheme + Uri.SchemeDelimiter + uri.Host + ":" + uri.Port;
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difference between variables inside and outside of __init__()
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Using Regular Expressions to Extract a Value in Java
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Full example:
private static final Pattern p = Pattern.compile("^([a-zA-Z]+)([0-9]+)(.*)");
public static void main(String[] args) {
// create matcher for pattern p and given string
Matcher m = p.matcher("Testing123Testing");
// if an occurrence if a pattern was foun...
How to squash commits in git after they have been pushed?
This gives a good explanation of squashing multiple commits:
8 Answers
8
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How do I get the key at a specific index from a Dictionary in Swift?
...ible that you could add the key "foo" and the internal representation will completely reorder the dictionary. A dictionary is an unordered collection of key-value pairs. Therefore, the answer above is making dangerous assumptions that do not hold true.
– Jack Lawrence
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What's the difference between a mock & stub?
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