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Which terminal command to get just IP address and nothing else?
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You can write a script that only return the IP like:
/sbin/ifconfig eth0 | grep 'inet addr' | cut -d: -f2 | awk '{print $1}'
For MAC:
ifconfig | grep "inet " | grep -v 127.0.0.1 | cut -d\ -f2
Or for linux system
hostname -i | awk '{print $3}' # Ubuntu
hostname -i # Debian
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Best way to test if a generic type is a string? (C#)
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answered Aug 28 '08 at 2:08
Matt HamiltonMatt Hamilton
183k5959 gold badges376376 silver badges317317 bronze badges
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What should a Multipart HTTP request with multiple files look like? [duplicate]
... dot (".").
POST /cgi-bin/qtest HTTP/1.1
Host: aram
User-Agent: Mozilla/5.0 Gecko/2009042316 Firefox/3.0.10
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip,deflate
Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7
Keep-Alive...
Visual Studio, Find and replace, regex
...<whatever.h> using find and replace functionality in Visual Studio 2005. I used the regex \#include \"[a-z\.h]+\" to find the include statement. But I am wondering how frame the replace regex.
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How to find the JVM version from a program?
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10 Answers
10
Active
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How to check if running as root in a bash script
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430
The $EUID environment variable holds the current user's UID. Root's UID is 0. Use something like...
What is the point of Lookup?
... (Type type in lookup["System"])
{
Console.WriteLine("{0}: {1}",
type.FullName, type.Assembly.GetName().Name);
}
}
}
(I'd normally use var for most of these declarations, in normal code.)
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AngularJS ng-if with multiple conditions
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edited Nov 8 '19 at 15:09
Edric
15.5k99 gold badges5656 silver badges7171 bronze badges
answered Nov ...
Does Ruby have a string.startswith(“abc”) built in method?
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340
It's called String#start_with?, not String#startswith: In Ruby, the names of boolean-ish methods...
Convert Array to Object
... It will return the target object.
Object.assign({}, ['a','b','c']); // {0:"a", 1:"b", 2:"c"}
The own length property of the array is not copied because it isn't enumerable.
Also, you can use ES6 spread syntax to achieve the same result:
{ ...['a', 'b', 'c'] }
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