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Flatten an Array of Arrays in Swift

... as it returns a lazy collection instead of a new array, but can always be converted to an array when passed to Array() initialiser like in the example above. share | improve this answer | ...
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How do you compare two version Strings in Java?

... converted on Kotlin stackoverflow.com/a/61795721/6352712 – Serg Burlaka May 14 at 13:04 ...
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Undefined reference to static class member

...it (1) can be used as an lvalue only if it has been defined but (2) can be converted to an rvalue without being defined? – j_random_hacker May 29 '09 at 10:51 ...
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What is a “surrogate pair” in Java?

... does not support UTF-32 "????".equals("\u1F309") // false 3. You can convert Unicode character to Java String "????".equals(new String(Character.toChars(0x0001F309))) //true 4. String.substring() does not consider supplementary characters "????????".substring(0,1) //"?" "????????".substri...
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android pick images from gallery

...ll example for request permission (if need), pick image from gallery, then convert image to bitmap or file AndroidManifesh.xml <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/> Activity class MainActivity : AppCompatActivity() { override fun onCreate(savedIns...
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string to string array conversion in java

I have a string = "name"; I want to convert into a string array. How do I do it? Is there any java built in function? Manually I can do it but I'm searching for a java built in function. ...
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How do I make my string comparison case insensitive?

...e best would be using s1.equalsIgnoreCase(s2): (see javadoc) You can also convert them both to upper/lower case and use s1.equals(s2) share | improve this answer | follow ...
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When to use std::size_t?

...ff_t is long on 32 and 64 bit systems. This means that you always have to convert to and from size_t whenever you interact with a std::containers, which not very beautiful. But on a going native conference the authors of c++ mentioned that designing std::vector with an unsigned size_t was a mistake...
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Swift double to string

...g = double.description update Xcode 7.1 • Swift 2.1: Now Double is also convertible to String so you can simply use it as you wish: let double = 1.5 let doubleString = String(double) // "1.5" Swift 3 or later we can extend LosslessStringConvertible and make it generic Xcode 11.3 • Swift 5.1 ...
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Remove unwanted parts from strings in a column

...2 3 11:00 44 4 12:00 30 5 13:00 110 If you need the result converted to an integer, you can use Series.astype, df['result'] = df['result'].str.replace(r'\D', '').astype(int) df.dtypes time object result int64 dtype: object If you don't want to modify df in-place, use Dat...