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How can I escape square brackets in a LIKE clause?
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The ESCAPE keyword is required if you want to use a custom escape character (the backslash is indeed custom).
– Ryan Kohn
Oct 30 '12 at 14:59
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What is the single most influential book every programmer should read? [closed]
If you could go back in time and tell yourself to read a specific book at the beginning of your career as a developer, which book would it be?
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Are Swift variables atomic?
...o redraw a view when the property is changed to a different value; that is now done easier using didSet.
– gnasher729
Jun 11 '14 at 9:22
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How do I sort an observable collection?
.... For larger collections watch out for the number of collection changed notifications.
I have updated my code to improve performance (thanks to nawfal) and to handle duplicates which no other answers here do at time of writing. The observable is partitioned into a left sorted half and a right unsort...
How to read keyboard-input?
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try
raw_input('Enter your input:') # If you use Python 2
input('Enter your input:') # If you use Python 3
and if you want to have a numeric value
just convert it:
try:
mode=int(raw_input('Input:'))
except ValueError:
print "Not a number"
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OpenJDK availability for Windows OS [closed]
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Update (2019): OpenJDK Updates Project Builds for 8 and 11 are available now.
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How can I capture the result of var_dump to a string?
...rray(
)),
'resource' => NULL, // Note that this resource pointer is now NULL
'null' => NULL,
)
var_dump ($debug_dump in above example):
array(8) {
["bool"]=>
bool(false)
["int"]=>
int(1)
["float"]=>
float(3.14)
["string"]=>
string(11) "hello world"
["arr...
How can I split and parse a string in Python?
...]: ['2.7.0', 'bf4fda703454']
This splits the string at every underscore. If you want it to stop after the first split, use "2.7.0_bf4fda703454".split("_", 1).
If you know for a fact that the string contains an underscore, you can even unpack the LHS and RHS into separate variables:
In [8]: lhs, ...
How to access command line parameters?
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println(args[0]);
}
It seems that Rust is still pretty volatile right now with even standard IO, so this may become out of date fairly quickly.
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_=> what does this underscore mean in Lambda expressions?
...same thing as in this example, even though _ has absolutely no special significance in Ruby.
– Jörg W Mittag
May 6 '10 at 5:33
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