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How to check if a file exists in Go?
... function solely intended to check if a file exists or not (like Python's os.path.exists ). What is the idiomatic way to do it?
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How can I sort arrays and data in PHP?
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Might be a bit of a big edit: gist.github.com/Rizier123/24a6248758b53245a63e839d8e08a32b but if you think it is an improvement and I included everything essential I can apply it.
– Rizier123
Jun 2 '16 at 16:30
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Does MSTest have an equivalent to NUnit's TestCase?
...a4b5", "345")]
[DataRow("3&5*", "35")]
[DataRow("123", "123")]
public void StripNonNumeric(string before, string expected)
{
string actual = FormatUtils.StripNonNumeric(before);
Assert.AreEqual(expected, actual);
}
}
Again, V...
How to pattern match using regular expression in Scala?
...Regex(sc.parts.mkString, sc.parts.tail.map(_ => "x"): _*)
}
scala> "123" match { case r"\d+" => true case _ => false }
res34: Boolean = true
Even better one can bind regular expression groups:
scala> "123" match { case r"(\d+)$d" => d.toInt case _ => 0 }
res36: Int = 123
sc...
How can I safely create a nested directory?
What is the most elegant way to check if the directory a file is going to be written to exists, and if not, create the directory using Python? Here is what I tried:
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How to find the operating system version using JavaScript?
How can I find the OS name and OS version using JavaScript?
13 Answers
13
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How to access environment variable values?
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Environment variables are accessed through os.environ
import os
print(os.environ['HOME'])
Or you can see a list of all the environment variables using:
os.environ
As sometimes you might need to see a complete list!
# using get will return `None` if a key is not...
Python list directory, subdirectory, and files
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Use os.path.join to concatenate the directory and file name:
for path, subdirs, files in os.walk(root):
for name in files:
print os.path.join(path, name)
Note the usage of path and not root in the concatenation, sinc...
How do I check whether a file exists without exceptions?
...open it.
If you're not planning to open the file immediately, you can use os.path.isfile
Return True if path is an existing regular file. This follows symbolic links, so both islink() and isfile() can be true for the same path.
import os.path
os.path.isfile(fname)
if you need to be sure it...
Recursive sub folder search and return files in a list python
... are supplied so you can prune it if there are folders that you don't wish os.walk to recurse into.
import os
result = [os.path.join(dp, f) for dp, dn, filenames in os.walk(PATH) for f in filenames if os.path.splitext(f)[1] == '.txt']
Edit:
After the latest downvote, it occurred to me that glob ...