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Easy way to list node modules I have npm linked?
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edited Jul 24 '14 at 15:06
answered Jul 24 '14 at 14:13
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ng-options with simple array init
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306
You actually had it correct in your third attempt.
<select ng-model="myselect" ng-options=...
Print function log /stack trace for entire program using firebug
...lpful.
– Ravi Teja
Apr 4 '17 at 11:30
✚1 console.warn('[WARN] CALL STACK:', new Error().stack);
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Get Base64 encode file-data from Input Form
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+50
It's entirely possible in browser-side javascript.
The easy way:
The readAsDataURL() method might already encode it as base64 for yo...
How to convert hex to rgb using Java?
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answered Nov 9 '10 at 1:27
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3,74222 gold badges1818 silver badges1717 bronze badges
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IntelliJ IDEA JDK configuration on Mac OS
I am using IntelliJ IDEA 10. Every time when I create a new project, it is asking me to choose JDK for this project. Anyone know how I can configure it and make it easy to use?
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How can I use a file in a command and redirect output to the same file without truncating it?
...can use a temporary file though.
#!/bin/sh
tmpfile=$(mktemp)
grep -v 'seg[0-9]\{1,\}\.[0-9]\{1\}' file_name > ${tmpfile}
cat ${tmpfile} > file_name
rm -f ${tmpfile}
like that, consider using mktemp to create the tmpfile but note that it's not POSIX.
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How to read a text file reversely with iterator in C#
I need to process a large file, around 400K lines and 200 M. But sometimes I have to process from bottom up. How can I use iterator (yield return) here? Basically I don't like to load everything in memory. I know it is more efficient to use iterator in .NET.
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How do I print a double value without scientific notation using Java?
...8;
System.out.printf("dexp: %f\n", dexp);
This will print dexp: 12345678.000000. If you don't want the fractional part, use
System.out.printf("dexp: %.0f\n", dexp);
This uses the format specifier language explained in the documentation.
The default toString() format used in your original code ...
How to input a regex in string.replace?
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+150
This tested snippet should do it:
import re
line = re.sub(r"</?\[\d+>", "", line)
Edit: Here's a commented version explaining...