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What's the best way to iterate over two or more containers simultaneously
...tage of your indices implementation in comparison to boost counting_range? One could simply use boost::counting_range(size_t(0), containerA.size())
– SebastianK
Nov 6 '14 at 13:11
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Loop through a date range with JavaScript
Given two Date() objects, where one is less than the other, how do I loop every day between the dates?
10 Answers
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DISTINCT for only one column
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@Cybernate One complication: My inner SELECT needs a WHERE condition. I'm thinking the row numbers will be assigned to all rows in the table. This syntax is just a little beyond me. Any chance of an update that would guarantee one row w...
How to use if - else structure in a batch file?
...e test of A fails, then he whole of the inner if-else will be ignored.
As one of the answers mentioned, in this case only one of the tests can succeed so the 'else' is not needed, but of course that only works in this example, it isn't a general solution for doing if-else.
There are lots of ways a...
Why are empty strings returned in split() results?
...results, you may want to look at the filter function.
Example:
f = filter(None, '/segment/segment/'.split('/'))
s_all = list(f)
returns
['segment', 'segment']
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android layout: This tag and its children can be replaced by one and a compound drawable
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Merge the TextView and the ImageView into one, by using TextView's setCompoundDrawable*() methods, or using android:drawableLeft.
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Is non-blocking I/O really faster than multi-threaded blocking I/O? How?
...ork server program that shall handle 1000 clients connected in parallel:
One thread per connection (can be blocking I/O, but can also be non-blocking I/O).
Each thread requires memory resources (also kernel memory!), that is a disadvantage. And every additional thread means more work for the sched...
How to make rounded percentages add up to 100%
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Since none of the answers here seem to solve it properly, here's my semi-obfuscated version using underscorejs:
function foo(l, target) {
var off = target - _.reduce(l, function(acc, x) { return acc + Math.round(x) }, 0);
r...
JPA: How to have one-to-many relation of the same Entity type
... is possible. This is a special case of the standard bidirectional @ManyToOne/@OneToMany relationship. It is special because the entity on each end of the relationship is the same. The general case is detailed in Section 2.10.2 of the JPA 2.0 spec.
Here's a worked example. First, the entity cla...
How does a hash table work?
...and easier to search, but still you don't want to search sequentially from one end of the library (or list) to the other.
You want something that, with the title of the book, can give you the right spot at once, so all you have to do is just stroll over to the right shelf, and pick up the book.
Bu...