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Convert a PHP script into a stand-alone windows executable
I want to automate a fairly simple task. For this I have written a small PHP script which I run from the command line using PHP-CLI. Now I want to hand over this script to someone but I do not want to:
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How can I check if a URL exists via PHP?
How do I check if a URL exists (not 404) in PHP?
22 Answers
22
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Best way to create an empty object in JSON with PHP?
...ght therefor say that your code is valid and that it's the method to use.
PHP: Objects - Manual
If a value of any other type is converted to an object, a new instance of the stdClass built-in class is created. If the value was NULL, the new instance will be empty.
.. but, try to keep it safe!
Tho...
Stop caching for PHP 5.5.3 in MAMP
Installed MAMP on a new Macbook with PHP 5.5.3.
9 Answers
9
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Passing arrays as url parameter
...wever, there's a simpler way to do this:
$url = 'http://example.com/index.php?';
$url .= 'aValues[]=' . implode('&aValues[]=', array_map('urlencode', $aValues));
If you want to do this with an associative array, try this instead:
PHP 5.3+ (lambda function)
$url = 'http://example.com/ind...
Why check both isset() and !empty()
... @karim IMO empty is one of the most misunderstood functions in PHP. The tiny snippet about "no warning is generated" is very easy to overlook. I had to scan the documentation myself a few times to spot it to post it here.
– deceze♦
Dec 30 '10 at 4...
PHP mkdir: Permission denied problem
I am trying to create a directory with PHP mkdir function but I get an error as follows: Warning: mkdir() [function.mkdir]: Permission denied in ... . How to settle down the problem?
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PHP_SELF vs PATH_INFO vs SCRIPT_NAME vs REQUEST_URI
I am building a PHP application in CodeIgniter. CodeIgniter sends all requests to the main controller: index.php . However, I don't like to see index.php in the URI. For example, http://www.example.com/faq/whatever will route to http://www.example.com/index.php/faq/whatever . I need a reliable...
Reset keys of array elements in php?
...s
foreach($input as &$val) {
$val = array_values($val);
}
http://php.net/array_values
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PHP Fatal error: Cannot redeclare class
...x situation). The include_once tip helps to clarify an obscure feature of PHP.
– DavidHyogo
Mar 20 '13 at 2:12
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