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Soft keyboard open and close listener in an activity in Android
...
@tsig your +100 solution depends on specific screen. Failed on tablets and hdpi phones. I used correction as ten percent of device height. That means if view height is lower than screenHeight - 10% the keyboard is open. else keyboard is ...
data.frame rows to a list
...eresting solutions:
data("Batting", package = "Lahman")
x <- Batting[1:10000, 1:10]
library(benchr)
library(purrr)
benchmark(
split = split(x, seq_len(.row_names_info(x, 2L))),
mapply = .mapply(function(...) structure(list(...), class = "data.frame", row.names = 1L), x, NULL),
purrr ...
Android canvas draw rectangle
...h(0);
paint.setStyle(Paint.Style.STROKE);
canvas.drawRect(100, 100, 200, 200, paint);
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【HarmonyOS】编译、测试全流程 - HarmonyOS NEXT - 清泛IT社区，为创新赋能！
...管理」
3. 添加设备，输入设备名称和 UDID（最多可注册 100 台设备）
Step 3：开启开发者模式
1. 在鸿蒙设备上，进入「设置」->「关于手机」
2. 连续点击「版本号」7次，开启开发者模式
3. 进入「设置」->「系统和更新...
jquery's append not working with svg element?
... return el;
}
var circle= makeSVG('circle', {cx: 100, cy: 50, r:40, stroke: 'black', 'stroke-width': 2, fill: 'red'});
document.getElementById('s').appendChild(circle);
circle.onmousedown= function() {
alert('hello');
};
</script&g...
MySQL dump by query
...to just mysqldump all tables.
mysqldump --tables myTable --where="id < 1000"
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How to input a regex in string.replace?
...gt; and then there are cases ... where the<[99> number ranges from 1-100</[99>.
and there are many other lines in the txt files
with<[3> such tags </[3>"""
result = pattern.sub("", subject)
print(result)
If you want to learn more about regex I recomend to read Regular Ex...
When should I use uuid.uuid1() vs. uuid.uuid4() in python?
...s.
You can create duplicates by creating more than 214 uuid1 in less than 100ns, but this is not a problem for most use cases.
uuid4() generates, as you said, a random UUID. The chance of a collision is really, really, really small. Small enough, that you shouldn't worry about it. The problem is, ...
Histogram Matplotlib
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import matplotlib.pyplot as plt
import numpy as np
mu, sigma = 100, 15
x = mu + sigma * np.random.randn(10000)
hist, bins = np.histogram(x, bins=50)
width = 0.7 * (bins[1] - bins[0])
center = (bins[:-1] + bins[1:]) / 2
plt.bar(center, hist, align='center', width=width)
plt.show()
The...
Scala Doubles, and Precision
... another solution without BigDecimals
Truncate:
(math floor 1.23456789 * 100) / 100
Round:
(math rint 1.23456789 * 100) / 100
Or for any double n and precision p:
def truncateAt(n: Double, p: Int): Double = { val s = math pow (10, p); (math floor n * s) / s }
Similar can be done for the r...