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PHP Fatal error: Call to undefined function json_decode()
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I came back to mention that it appears as if 5.5.0 is fine with JSON, it is only 5.5.1 that breaks.
– MirroredFate
Aug 16 '13 at 19:35
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Can I mix MySQL APIs in PHP?
...are right :) Reading the manual shows that you are correct. What probably happened is, that mysql_real_escape_string() will silently try make a connection with the default parameters which then worked for OP. So it just made the connection to get the character set. So OP has 2 connections
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UITableViewCell Separator disappearing in iOS7
...gory. Since this requires method swizzling, I went for the simple subclass approach.
– Ortwin Gentz
Jul 2 '14 at 11:20
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Get individual query parameters from Uri [duplicate]
...exact collectiontype you are looking for, but nevertheless useful.
Edit: Apparently, if you supply the complete url to ParseQueryString it will add 'http://example.com/file?a' as the first key of the collection. Since that is probably not what you want, I added the substring to get only the releva...
Django Server Error: port is already in use
...ted with it.
kill -9 PID
in my case
kill -9 6599
Now run your Django app.
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Numeric for loop in Django templates
... And that was one of two lines of code I had to chance in transitioning an app to Python3.
– Dave W. Smith
Apr 13 '16 at 0:45
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How to create an array for JSON using PHP?
...array);
Normally you use json_encode to read data from an ios or android app. so make sure you do not echo anything else other than the accurate json array.
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NHibernate.MappingException: No persister for: XYZ
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Sounds like you forgot to add a mapping assembly to the session factory configuration..
If you're using app.config...
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<property name="show_sql">true</property>
<property name="query.substitutions">true 1, false 0, yes 'Y', no ...
Java - get the current class name?
All I am trying to do is to get the current class name, and java appends a useless non-sense $1 to the end of my class name. How can I get rid of it and only return the actual class name?
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How do I get the dialer to open with phone number displayed?
... with back button after opening dialer in new intent. I can get back to my application only in 3 back button press (it shows me several screens of dialer which I didnt open - the dialer itself, create new contact screen, favourites). Does somebody knows how to get back to app with only 1 back button...