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How to combine date from one field with time from another field - MS SQL Server

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown. 1...
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Viewing unpushed Git commits

...o much so I did git config --global alias.ahead "log origin/master..HEAD --oneline" so that I can quickly find out where I am. Even more candy: for i in *; do echo $i && git ahead 2>/dev/null; done – Jamie Feb 28 '12 at 2:50 ...
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How can I count the occurrences of a list item?

... If you only want one item's count, use the count method: >>> [1, 2, 3, 4, 1, 4, 1].count(1) 3 Don't use this if you want to count multiple items. Calling count in a loop requires a separate pass over the list for every count call,...
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What is the maven-shade-plugin used for, and why would you want to relocate Java packages?

I found the maven-shade-plugin being used in someone's pom.xml. I've never used maven-shade-plugin before (and I'm a Maven n00b) so I tried to understand the reason for using this and what it does. ...
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What are .NET Assemblies?

...an be executed by the .NET runtime environment. A .NET program consists of one or more assemblies. share | improve this answer | follow | ...
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Composer: how can I install another dependency without updating old ones?

I have a project with a few dependencies and I'd like to install another one, but I'd like to keep the others the way they are. So I've edited the composer.json , but if I run composer install , I get the following output: ...
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Ignore mapping one property with Automapper

...oo, Bar>().ForMember(x => x.Blarg, opt => opt.Ignore()); It's in one of the comments at his blog. share | improve this answer | follow | ...
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select and update database record with a single queryset

...statements on the same queryset rather than having to do two queries: - one to select the object - and one to update the object ...
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Set custom HTML5 required field validation message

I have one form with many input fields. I have put html5 validations 11 Answers 11 ...
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Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array

... // JS by default uses a crappy string compare. // (we use slice to clone the array so the // original array won't be modified) let results = []; for (let i = 0; i < sorted_arr.length - 1; i++) { if (sorted_arr[i + 1] == sorted_arr[i]) { results.push(sorted_arr[i]); ...