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What would cause an algorithm to have O(log n) complexity?

...o have that log2 16 = 4. Hmmm... what about 128? 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1 This took seven steps, and log2 128 = 7. Is this a coincidence? Nope! There's a good reason for this. Suppose that we divide a number n by 2 i times. Then...
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Android Studio - Where can I see callstack while debugging an android app?

... edited Jan 28 '18 at 16:53 Basem Saadawy 1,74822 gold badges1919 silver badges2929 bronze badges answer...
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Map to String in Java

... answered May 13 '10 at 15:56 BalusCBalusC 954k342342 gold badges34193419 silver badges34053405 bronze badges ...
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Xcode Product -> Archive disabled

... 1360 You've changed your scheme destination to a simulator instead of Generic iOS Device. That's w...
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How can I merge two hashes without overwritten duplicate keys in Ruby?

... 235 If you have two hashes, options and defaults, and you want to merge defaults into options witho...
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Where should virtualenvs be created?

... Michael Hays 1,67433 gold badges1111 silver badges1717 bronze badges answered Aug 29 '12 at 19:06 David RobinsonDavid R...
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LINQ Distinct operator, ignore case?

... 233 StringComparer does what you need: List<string> list = new List<string>() { "O...
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What is the difference between Directory.EnumerateFiles vs Directory.GetFiles?

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Count, size, length…too many choices in Ruby?

... an element or predicate and count only those items that match. > [1,2,3].count{|x| x > 2 } => 1 In the case where you don't provide a parameter to count it has basically the same effect as calling length. There can be a performance difference though. We can see from the source code f...
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Force Screen On

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