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Android ADB device offline, can't issue commands
...ui
Now my development tools are:
SDK rev 16.0.2
SDK tools rev 21.1
SDK API 17, rev 2
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What's the Best Way to Shuffle an NSMutableArray?
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If you import GameplayKit, there is a shuffled API:
https://developer.apple.com/reference/foundation/nsarray/1640855-shuffled
let shuffledArray = array.shuffled()
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Secure random token in Node.js
...the same thing, but using the async version of randomBytes. See nodejs.org/api/…
– Alec Thilenius
Sep 28 '16 at 19:50
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Shortcut for creating single item list in C#
...which is "alpha" and it's based on a very stable and heavily used internal API.)
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Best Practice: Software Versioning [closed]
... captures a different intent:
the major segment indicates breakage in the API
the minor segment indicates "externally visible" changes
the service segment indicates bug fixes and the change of development stream
the qualifier segment indicates a particular build
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Using jQuery to center a DIV on the screen
...ou need the jqueryUI library to use .position() as a function. Check out: api.jqueryui.com/position/
– jake
Jun 15 '13 at 17:04
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Jackson with JSON: Unrecognized field, not marked as ignorable
... this is a very stupid default setting imho, if you add a property to your api, the whole serialization fails
– headsvk
Oct 5 '16 at 17:00
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How to wait for async method to complete?
... This an inefficient use of the various asynchronous mechanisms exposed by APIs that go to great efforts to provide them.
The answer at "await" doesn't wait for the completion of call has several, more detailed, explanations of these keywords.
Meanwhile, @Stephen Cleary's guidance about async void...
How do I get the width and height of a HTML5 canvas?
...e canvas to allow you to draw into it. You can think of the context as the API to the canvas, that provides you with the commands that enable you to draw on the canvas element.
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Merging objects (associative arrays)
...: 110} // Pseudo JS
(assoc. arrays are objects in js)
look here: http://api.jquery.com/jQuery.extend/
edit: Like rymo suggested, it's better to do it this way:
obj3 = $.extend({}, obj1, obj2);
obj3 == {a: 4, b: 2, c: 110}
As here obj1 (and obj2) remain unchanged.
edit2: In 2018 the way ...