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How to extract the hostname portion of a URL in JavaScript
... ahve been searching for method to extract the of the url I'm getting from api. It was so simple. I had only read it in url with new URL. Thank you.
– Nodirabegimxonoyim
Jan 22 '19 at 10:06
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Assigning default value while creating migration file
...s_count, :integer, :null => false, :default => 0
... and read Rails API
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How do I detach objects in Entity Framework Code First?
...t is actually why this method exists. Using this approach in ObjectContext API is little bit more complicated.
– Ladislav Mrnka
Apr 8 '11 at 21:15
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Specify format for input arguments argparse python
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@StevenVascellaro yes, but that's what the API defines; "takes a single string argument" per the quote from the docs.
– jonrsharpe
Feb 13 '18 at 21:11
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Best way to create custom config options for my Rails app?
...Rails.configuration.neo4j['port'] #=>7474
More info
Rails official API document describes config_for method as:
Convenience for loading config/foo.yml for the current Rails env.
If you do not want to use a yaml file
As Rails official guide says:
You can configure your own code t...
Thread-safe List property
...ook likes they added this in .net core 2.0 docs.microsoft.com/en-gb/dotnet/api/…
– Cirelli94
Mar 7 '18 at 15:00
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Input from the keyboard in command line application
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It's actually not that easy, you have to interact with the C API. There is no alternative to scanf. I've build a little example:
main.swift
import Foundation
var output: CInt = 0
getInput(&output)
println(output)
UserInput.c
#include <stdio.h>
void getInput(int *outp...
How can I disable a button on a jQuery UI dialog?
... }
}
]
});
Then, elsewhere, you should be able to use the API for the jquery UI button:
$("#button-ok").button("disable");
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Retrieving a List from a java.util.stream.Stream in Java 8
...use forEachOrdered to ensure correct ordering. The intention of the Stream API designers is that you will use collector in this situation, as below.]
An alternative is
targetLongList = sourceLongList.stream()
.filter(l -> l > 100)
.collect(Collectors.toList());
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How to create an array of 20 random bytes?
...ong random number generator (also thread safe) without using a third party API, you can use SecureRandom.
Java 6 & 7:
SecureRandom random = new SecureRandom();
byte[] bytes = new byte[20];
random.nextBytes(bytes);
Java 8 (even more secure):
byte[] bytes = new byte[20];
SecureRandom.getInsta...